147
147x3 = 441 x3 = 441/147 x3 = 3 x = 31/3 x ≈ 1.4
21
441 is a composite number because it has factors other than 1 and itself. It is not a prime number.The 9 factors of 441 are 1, 3, 7, 9, 21, 49, 63, 147, and 441. It is a square number (21 x 21), so it has an odd number of factors.The factor pairs of 441 are 1 x 441, 3 x 147, 7 x 63, 9 x 49, and 21 x 21.The proper factors of 441 are 1, 3, 7, 9, 21, 49, 63, and 147 or,if the definition you are using excludes 1, they are 3, 7, 9, 21, 49, 63, and 147.The prime factors of 441 are 3, 3, 7, and 7. Note: There is repetition of these factors, so if the prime factors are being listed instead of the prime factorization, usually only the distinct prime factors are listed.The distinct prime factors of 441 are 3 and 7.The prime factorization of 441 is 3 x 3 x 7 x 7 or, in exponential form, 32 x 72.
(147,3)(63,7)(49,9)
yes 7 is dividable by 5670 the answer is 810
NO
No
No, it is not.
No, it is not.
Dividable
2 is the only prime number dividable by 2. to be a prime number, it must only be dividable by 1 and itself. This is the reason why 2 is the only prime number dividable by 2. If any other number was dividable by two then it would not be prime any more
it means to separate
1 * 441 equals 441
Any number dividable by six must also be dividable by 3 as well as by 2. Nice Question!
niether
By two and a half