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It is a quadratic equation and its solutions are: x = -3/2 and x = 3
What else can I help you with?
5x 4 - 3x 5 2x - 9?
Here is how you solve this problem... 5x*4-3x*5*2x-9= (Combine like-terms) 5x-3x*2x= 2x*2x=(2x)2 (Add the rest of the problem) (2x)2*4*5-9=(2x)2*20-9 (2x)2*11 (2x)2 *11= your answer
X minus 2 divided by 3x plus 9 times 2x plus 6 divided by 2x minus 4?
I assume you wish to simplify the expression (x - 2)/(3x + 9) . (2x + 6)/(2x - 4) = (x - 2)(2x + 6) / [(3x + 9)(2x - 4)] = 2(x - 2)(x + 3) / [6(x + 3)(x - 2)] = 1/3.
3x² -2x -2 factorize?
3x2-2x-2 = (3x-3.645751311)(x+0.5485837704) when factored with the help of the quadratic equation formula
What is the result of adding -3x -5x 1 and 8x - 2x - 9?
If you mean: -3x-5x+1+8x-2x-9 then the result is -2x-8
3x plus 5x equals 2x plus 2?
3x + 5x = 2x + 28x = 2x + 26x = 2x = (2/6) = 1/3
5x 4 - 3x 5 2x - 9?
Here is how you solve this problem... 5x*4-3x*5*2x-9= (Combine like-terms) 5x-3x*2x= 2x*2x=(2x)2 (Add the rest of the problem) (2x)2*4*5-9=(2x)2*20-9 (2x)2*11 (2x)2 *11= your answer
How do you expand 3x-2 2x-9?
3x-2 and 2x-9, now for this it kind of depends on how the equation is set out if it set out likw this 3x-2+2x-9 then you would answer it like this: -6x+-18x= 12x
3x + 9 = 2x + 10?
3x+9=2x+10 3x+9-2x=10 9+x=10 x=1
X minus 2 divided by 3x plus 9 times 2x plus 6 divided by 2x minus 4?
I assume you wish to simplify the expression (x - 2)/(3x + 9) . (2x + 6)/(2x - 4) = (x - 2)(2x + 6) / [(3x + 9)(2x - 4)] = 2(x - 2)(x + 3) / [6(x + 3)(x - 2)] = 1/3.
3x-3 equals 2x plus 6?
3x - 3 = 2x + 6 3x = 2x + 9 x = 9
2x plus 9 equals 49 -3x?
2x+9 = 49-3x 2x+3x = 49-9 5x = 40 x = 8
How would you evaluate the indefinite integral -2xcos3xdx?
Integrate by parts: ∫ uv dx = u ∫ v dx - ∫ (u' ∫ v dx) dx Let u = -2x Let v = cos 3x → u' = d/dx -2x = -2 → ∫ -2x cos 3x dx = -2x ∫ cos 3x dx - ∫ (-2 ∫ cos 3x dx) dx = -2x/3 sin 3x - ∫ -2/3 sin 3x dx = -2x/3 sin 3x - 2/9 cos 3x + c
2(x+5)=3x+1?
2(x+5) =3X+1 => 2x+10-3x-1=0. => -x+9 => x=9
-2x plus 3y equals 9?
y=-2/3x
How do you find the perimeter of 2x and 3x?
(2x x 3x) x 2 = 12x (2x times 3x times 2)
What is the quotient when (x 3) is divided into the polynomial 2x2 3x - 9?
To find the quotient when (2x^2 + 3x - 9) is divided by (x^3), we note that the degree of the divisor (x^3) is greater than the degree of the dividend (2x^2 + 3x - 9). Therefore, the quotient is (0) since (x^3) cannot divide (2x^2 + 3x - 9) without resulting in a fractional expression.
-3x plus 2 equals 2x-8?
-3x+2 = 2x-8 8+2 = 2x+3x 10 = 5x x = 2
