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Find the inverse of f x 3x plus 9?
f(x) = 3x + 9 y = 3x + 9 so 3x = y - 9 x = y/3 - 3 Therefore, the inverse function is g(x) = x/3 - 3
What is the inverse of 2x-8?
y = x² - 2x - 8 Swap x and y to find the inverse: x = y² - 2y - 8 Now get y by itself: y² - 2y = x + 8 (Complete the square): y² - 2y + 1 = x + 9 (y - 1)² = x + 9 y - 1 = ±√(x + 9) y = 1 ±√(x + 9) Then there are two functions: f(x) = 1 - √(x + 9) and f(x) = 1 + √(x + 9) but an inverse can only be one function. The functions above are a mirror image of the original function, but it is not an inverse (graph these functions). There is no inverse. Everything above is completely wrong. This is the inverse: (x+8)/2 I don't know where the x² came from in the first answer, but to work out the question as asked: if y=2x-8 y+8 = 2x (y+8)/2 = x so, as the above answer stated, (x+8)/2 is the answer.
What does y equals 3x plus y and y equals x-9 equal?
y = 3x + y => x = 0then y = x - 9 => y = 0 - 9 = -9.
What is Y 6x - 9?
y=6x-9
How do you factor this Y3 plus 2y2 - 81y - 162?
y3 + 2y2 - 81y -162 = y2(y+2) - 81(y+2) =(y+2)(y2-81) = (y+2)(y-9)(y+9)
