You cannot. The sum of 5 odd numbers is always odd. 30 is not odd.
The four consecutive odd numbers which add up to 120 are 27, 29, 31 and 33. It can be found out as follows: Let 'x' be the smallest odd number. The next odd numbers will be 'x+2', 'x+4', 'x+6'. The addition of these four numbers will give 120. Therefore, x+(x+2)+(x+4)+(x+6)=120 4x+12=120 x+3=30 Therefore, x=27.
Even. 2 x 3 = 6 for example
No, there is 6, 12, 18, 24 and so on so forth. Only half of them are odd.
21, 23, 25, 27, 29
the odd no. is 8 2*3=6 2*7=14 2*15=30
No. The bullet is too big. A 30-30 is a .30 caliber bullet. a .38 bullet is .357 caliber
The positive integer factors of 30 are: 1 2 3 5 6 10 15 30 The odd factors are therefore 1, 3, 5, 15
.254, if you multiply .245 by 30 your answer is 7.62 which the diameter of a 30 cal. bullet if you multiply .254 by 50 you will get 12.7 which the diameter of a 50 cal. bullet and so on.
A single 9mm bullet is about 3-6 cents. A 9mm Parabellum (Luger) CARTRIDGE is about .30-.55.
The sum of 3 odd numbers is odd while 30 is an even number. So there is not a valid answer in the normal sense. However, in base 9, 5 + 6 + 17 = 30 [In base 10, the above is 5 + 6 + 16 = 27]
You cannot. The sum of 5 odd numbers must be odd. 30 is not odd.You cannot. The sum of 5 odd numbers must be odd. 30 is not odd.You cannot. The sum of 5 odd numbers must be odd. 30 is not odd.You cannot. The sum of 5 odd numbers must be odd. 30 is not odd.
There are 6 odd digits.There are 6 odd digits.There are 6 odd digits.There are 6 odd digits.
The thirty-aught-six (30-06) bullet diameter is .308 in (7.62 mm) The "30" designates the projectile as 30 caliber, whilst the "06" indicates the year the round was adopted and standardized by the US Military.
20,000
You cannot. The sum of 5 odd numbers is always odd. 30 is not odd.
6, 18, 30, 42, 54, 66, 78, 90