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In much of the Western world, large numbers are grouped into thousands and powers of thousands - such as millions, billions, trillions etc. TO make large numbers easier to read, they are written in triplets comprising these "super-bases", with the triplets separated by commas.
In some European countries, however, the role of the comma and the decimal point are swapped.
The system of writing in triplets would not work with the Indic system where thousands are grouped in hundreds (for a lakh), and a hundred lakhs for a crore.
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How many different car license plates can be made using three letters followed by three digits if no letter can be repeated and zero cannot be used as the first digit?
Number of possible groups of 3 letters = 26 x 25 x 24 = 15,600. For each of these . . .Number of possible groups of 3 digits = 9 x 9 x 8 = 648 .Total number of possible distinct plates = 15,600 x 648 = 10,108,800
How many 6 digit numbers can be formed with 4 different digits?
The question can be re-stated as asking for the total number of permutations that can be derived from the following two groups of digits: AAABCD and AABBCD, where A, B, C and D are different. The number of ways of choosing the digit A, to be used three times, out of the ten digits {0, 1, 2, ... 9} is 10. Having done that, the number of ways of selecting 3 from the remaining 9 digits is 9C3 = (9*8*7)/(3*2*1) = 84. Thus there are 10*84 = 840 combinations of the form AAABCD. You now need all the distinct permutations of these 6 digits. The total number of permutations of 6 digits is 6! but because 3 of the digits are the same, these permutations are not all distinct. In fact, there are 6!/3! = 120 distinct permutations. That makes a total of 840*120 = 100800 such numbers. Next, the number of ways of choosing the digits A and B, each to be used twice, out of the ten digits {0, 1, 2, ... 9} is 10C2 = (10*9)/(2*1) = 45. Having done that, the number of ways of selecting C and D from the remaining 8 digits is 8C2 = (8*7)/(2*1) = 28. Thus there are 45*28 = 1260 combinations of the form AAABCD. You now need all the distinct permutations of these 6 digits. The total number of permutations of 6 digits is 6! but because 2 pairs of these digits are the same, these permutations are not all distinct. In fact, there are 6!/(2!*2!) = 180 distinct permutations. That makes a total of 1260*180 = 226800 such numbers. The grand total is, therefore, 100800 + 226800 = 327600 6-digit numbers made from 4 distinct digits.
If you have 18 plums can you find 6 different ways to show equal groups?
18 groups of 4
How many ways can you divide 32 equally?
6 ways. 32 divided by 1=32 32 divided by 2=16 32 divided by 4= 8 32 divided by 8 = 4 32 divided by 16= 2 32 divided by 32= 1
Is agreement concrete or abstract?
The word 'agreement' is an abstract noun as a word for an arrangement or decision made by two or more people, groups, or organizations; a word for a concept.The word 'agreement' is a concrete noun as a word for a written arrangement; a word for a document.
