In 1972, Heskestad proposed the following formula to calculate how fires grow:
Q = .tn
Q is the rate of heat release (kW)
. is the fire intensity coefficient (kW/sn)
t is time (sec)
n is 1, 2, 3
For most flaming fires except flammable liquids and a few others, n = 2.
When n = 2, this is called the T-squared growth rate.
Since the question refers to "how much greater" rather than "how much as great as", the answer is that: t squared is (t-1) times greater than t.
It is t2 (t squared). Anytime you multiply a number or a variable by itself, then it is squared. If it's multiplied by itself 3 times, then it's cubed, or t3
49+t
[5(s^2)(t^2)]/40st since it is multiplication you can separate the fraction; = (5/40)(s^2/s)(t^2/t) = (1/8)st or = st/8
Use the formula a^2 - b^2 = (a -b)(a + b). So: t^2 - (t - 1)^2 = [t - (t -1)][t + (t -1)] Now you can work and simplify the given expression. =(t - t +1)(t + t -1) =(1)(2t -1) = 2t -1
T squared is T times T. T squared and T squared appears to be the addition of T squared with itself. That answer would be 2T squared or 2T^2
_t(5t squared t+)
(6x + t)(3x + t)
t+t=2tand t*t= t squaredyou would only get t squared if you multiplied
t(t-1)
15t2 squared-t-15t+3=15t squared-14t+3
2t
t to the one quarter
72 = 49.72 + t = 49 + t
d/dt (t^2)=2t
Since the question refers to "how much greater" rather than "how much as great as", the answer is that: t squared is (t-1) times greater than t.
3 t squared (3t^2)