In 1972, Heskestad proposed the following formula to calculate how fires grow:
Q = .tn
Q is the rate of heat release (kW)
. is the fire intensity coefficient (kW/sn)
t is time (sec)
n is 1, 2, 3
For most flaming fires except flammable liquids and a few others, n = 2.
When n = 2, this is called the T-squared growth rate.
Since the question refers to "how much greater" rather than "how much as great as", the answer is that: t squared is (t-1) times greater than t.
It is t2 (t squared). Anytime you multiply a number or a variable by itself, then it is squared. If it's multiplied by itself 3 times, then it's cubed, or t3
49+t
[5(s^2)(t^2)]/40st since it is multiplication you can separate the fraction; = (5/40)(s^2/s)(t^2/t) = (1/8)st or = st/8
Use the formula a^2 - b^2 = (a -b)(a + b). So: t^2 - (t - 1)^2 = [t - (t -1)][t + (t -1)] Now you can work and simplify the given expression. =(t - t +1)(t + t -1) =(1)(2t -1) = 2t -1
"T squared" typically refers to the square of the variable "T" in mathematics, which means T multiplied by itself. When you see "T squared" and "T squared" together, it could indicate a comparison or relationship between two different quantities, both squared. This could be part of an equation or formula where both T and another variable are squared and compared in some way. It's important to consider the context in which these terms are used to fully understand their meaning and significance in the given situation.
_t(5t squared t+)
(6x + t)(3x + t)
t+t=2tand t*t= t squaredyou would only get t squared if you multiplied
t(t-1)
15t2 squared-t-15t+3=15t squared-14t+3
2t
t to the one quarter
72 = 49.72 + t = 49 + t
d/dt (t^2)=2t
Since the question refers to "how much greater" rather than "how much as great as", the answer is that: t squared is (t-1) times greater than t.
3 t squared (3t^2)