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Minus square root of 2, minus square root of 3, minus pi, minus e, etc. Or, to be a bit more fancy, 1 - pi, 2 - pi, 3 - pi, pi - 4, pi - 5, 2 - e, e - 3, square root of 2 minus 2, etc.

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Irrational number less than 0

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Q: What is an irrational number less than 0?

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Negative square root of 2 . Negative (pi) .

No. If the rational number is not zero, then such a product is irrational.

'pi' and 'e' both fit that description.

0 is not an irrational no. since it is a rational no. of the of 0/1.A number like Pi is irrational because it cannot be expressed as a fraction. When shown as a decimal it goes on for ever.Zero does neither of these. So it is a rational number.

No, they are not. An irrational number subtracted from itself will give 0, which is rational.

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Any number that is less than 0. Any rational irrational or integral number that is less than 0 is considered negative.

Negative square root of 2 . Negative (pi) .

Every irrational number, every rational number which is not an integer and every integer less than 2 falls into this category.

Not necessarily. 0 times any irrational number is 0 - which is rational.

No. 0 is a rational number and the product of 0 and any irrational number will be 0, a rational. Otherwise, though, the product will always be irrational.

Every irrational number, every rational number which is not an integer and every integer less than 2 falls into this category.

No, it is not.

No

The product of 0 and an irrational is 0 (a rational), the product of a non-zero rational and any irrational is always irrational.

Can be irrational or rational.1 [rational] * sqrt(2) [irrational] = sqrt(2) [irrational]0 [rational] * sqrt(2) [irrational] = 0 [rational]

The question cannot be answered because it is based on a false premise.The product of a (not an!) rational number and an irrational number need not be irrational. For eample, the product ofthe rational number, 0, and the irrational number, pi, is 0. The product is rational, not irrational!

The product of an irrational number and a rational number, both nonzero, is always irrational