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Q: What is define sets?

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Boolean algebra deals with logic and truth as it pertains to sets and possibilities. It uses the and, or and not operators to set up truth tables to define if a statement is true or not.

No, because equivalent sets are sets that have the SAME cardinality but equal sets are sets that all their elements are precisely the SAME. example: A={a,b,c} and B={1,2,3} equivalent sets C={1,2,3} and D={1,2,3} equal sets

3,4,5 1,2,3 these are sets of pythagorean triples

There is quite a lot of algebra devoted to solving problems involving sets, parts of sets, and concepts closely related to sets, such as subsets, cosets, and groups. You'll need to be more specific.

Sets contain elements. The intersection of sets (represented by an upside-down 'U') is the list of elements that are common in both sets. The union of sets (represented by 'U') is the list of all the elements in the relevant sets. E.g. If A={a,b,c,d,e,f} and B={a,e,i,o,u}: The intersection of A and B is {a,e}. The union of A and B is {a,b,c,d,e,f,i,o,u} (notice how repeating elements, e.g. 'a' and 'e', are only listed once even though they occur in both sets.)

Related questions

We don't know what kind of sets.

It is when two sets of ranges do not overlap

A set is a collection of well-defined and distinct objects.

Lighter weights, but more sets. Reps should be at a good pace.

A parent function refers to the simplest function as regards sets of quadratic functions

well, you take the opposite of the base of the integer and then you subtract pi from both sets.

i am also having the same doubt please tell me the answers if u know

A set is a collection of well defined and distinct objects, considered as an object in its own right.

Queries extract records from a table - according to the 'rules' the user sets for the query.

Low key

When someone sets up the ball and you quickly jump up and hit the ball as hard as you can

A Java set is a collection of things that do not contain duplicate elements. Duplicates are prohibited from Java sets.