(a-b)2 = a2 _ 2ab+b2
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a square minus b square
(a+b)(a-b)
(a + b + c)3 = a3 + b3 + c3 + 3(a2b + ab2 + b2c + bc2 + ca2 + ac2) + 6abc
the entire quadratic formula is x is equal to negative b plus or minus the square root b squared minus four(4) a c all over two(2) a (divided by 2)you may have trouble remembering this formula but you can fit it to the tune of pop goes the weasle.here ya go
Using the quadratic formula-- ((negative b plus or minus the square root of b squared minus 4ac) divided by (2a)) you'll want to google that so you can see it in numerical form. a, b, and c are the coefficiants of your three terms ( 2 is a, -5 is b, and 2 is c) The answer is (x-2)(2x-1).