The LCM of 154 and 198 is 1386.
66 = 198
Designate the number of women as w. Then 198/w = 3/4, or 198 = 3w/4, or w = 4 X(198/3) = 264.
14.0712473
198 is a composite number because it has factors other than 1 and itself. It is not a prime number.The 12 factors of 198 are 1, 2, 3, 6, 9, 11, 18, 22, 33, 66, 99, and 198.The factor pairs of 198 are 1 x 198, 2 x 99, 3 x 66, 6 x 33, 9 x 22, and 11 x 18.The proper factors of 198 are 1, 2, 3, 6, 9, 11, 18, 22, 33, 66, and 99 or,if the definition you are using excludes 1, they are 2, 3, 6, 9, 11, 18, 22, 33, 66, and 99.The prime factors of 198 are 2, 3, 3, and 11.The 3 distinct prime factors (listing each prime factor only once) of 198 are 2, 3, and 11.The prime factorization of 198 is 2 x 3 x 3 x 11 or, in index form (in other words, using exponents), 2 x 32 x 11.NOTE: There cannot be common factors, a greatest common factor, or a least common multiple of a single number because "common" refers to factors or multiples that two or more numbers have in common.
It is: 396/2 = 198
Just over 6 half lives.
one-quarter After 2.7 Days half of Gold remains. After another 2.7 days half of THAT half remains, which is 25% 5.4
Well, isn't that a happy little question! Half of 396 is like taking a big, beautiful painting and splitting it right down the middle. You'll end up with two equal parts, each with 198. Just imagine those two halves coming together to create a perfect balance on your canvas.
40 percent off 198 dollars = $118.840% off of $198= 40% discount applied to $198= $198 - (40% * $198)= $198 - (0.40 * $198)= $198 - $79.2= $118.8
At 2.7 days, half of the 800 atoms (400 atoms) would have decayed. At 8.1 days, three half-lives have passed, so only ( \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} = \frac{1}{8} ) of the original sample remains. Therefore, there are 100 atoms of Au-198 remaining in the sample after 8.1 days.
After 8.1 days, three half-lives have passed for Au-198 (2.7 days/half-life * 3 half-lives = 8.1 days). Each half-life reduces the number of atoms by half, so remaining atoms = 800 atoms * (1/2)^3 = 100 atoms.
30% of 198= 30% * 198= 0.3 * 198= 59.4
25% of 198= 25% * 198= 0.25 * 198= 49.5
198 itself, 198*2 = 396, 198*3 = 594, 198*4 = 792 etc
After 8.1 days, three half-lives have passed (8.1 days / 2.7 days = 3). With each half-life, the number of atoms is halved. Therefore, starting with 800 atoms, after three half-lives there would be 800 / 2 / 2 / 2 = 100 atoms remaining.
198