Horizontal lines have a slope of zero, and the slope of vertical lines is undefined. Parallel lines have equal slopes, and perpendicular lines have slopes that are negative reciprocals of each other. So we can say that: Two nonvertical lines are parallel if and only if they have the same slope. Two lines are perpendicular if and only if their slopes are negative reciprocals of each other. That is, if the slopes are m1 and m2, then: m1 = - 1/m2 or (m1)(m2) = -1
A M1 license allows you to operate any 2-wheel motorcycle or motor-driven cycle, including those 150cc or higher. A M2 license allows you to operate any motorized bicycle, moped, or any bicycle with an attached motor, up to 150cc
y = x2 + 2mx + n complete the square y + m2 = x2 + 2mx + m2 + n = (x + m)2 + n (x + m)2 = y + m2 - n x + m = √(y + m2 - n) x = -m + √(y + m2 - n)
Area = base * height = 5*(4a + b) m2 = (20a + 5b) m2
64 meters
What is the difference between M1 and M2?
If the slopes are m1 and m2 then m1*m2 = -1 or m2 = -1/m1.
M1 is what is outside the banking system: Your cash, coins, your checking account. M2 is: All of M1 plus, savings accounts, money in banks, small time deposits...etc .
M1, M2, M3, and M4 are typically used to refer to different measures of the money supply within an economy. Generally, M1 includes physical money and demand deposits, M2 adds savings deposits and money market funds to M1, M3 includes M2 plus large time deposits and institutional money market funds, while M4 is a broader measure that includes M3 plus all other assets.
if(m1>m2) f=m1; s=(m2>m3)?m1!m3 what its meaning of this?
M2 and M1 are measures of the money supply. M1 includes physical money, such as paper currency and coins, as well as demand deposits and other liquid assets that can be quickly converted into cash. M2 includes all of M1 plus savings deposits, time deposits, and other non-cash assets that can be easily converted into cash.
M1 money is transaction money, It includes: Coins of all denominations, Paper money including all types of notes, Checking accounts and Traveler's checks. M2 money is M1 money plus Close substitutes ( savings accounts/deposits).
weight, w = G * m1 * m2 / r^2, where G = the universal gravitational constant, m1 = the mass of the object, m2 = the mass of the earth, and r = the separation between the center of gravity of the object and that of the earth. w1 = G * m1 * m2 /(r1^2) -- > the weight when r = r1 w2 = G * m1 * m2 /(r2^2) -- > the weight when r = r2 Given: r2 = 4 * r1 w2 = G * m1 * m2 /(16 r1^2) = w1 / 16 Hence, the object will be 16 times lighter when it is situated 4 times farther away.
*Edit* M2 can print a box of paper in 3x plus 20 hours.
The force, written as an equation, is:F = G (m1)(m2) / r2, whereF is the Force between the massesG is the gravitational constant (~= 6.674 x 10-11 N m2/kg2)m1 is one of the massesm2 is the other massr is the distance between the masses (center to center)Take the formula, and solve for r (I'll show the steps): Fold = G (m1)(m2) / r2.(r2)(Fold)= G (m1)(m2)(r2)= G (m1)(m2) / (Fold)r= √ [ G (m1)(m2) / (Fold) ]Plug the formula into itself, but remember, r = 3r (it tripled).Fnew= G (m1)(m2) / (3r)2.Fnew= G (m1)(m2) /(3√ [ G (m1)(m2) / (Fold) ])2.Fnew=G (m1)(m2)/(32G (m1)(m2) / (Fold) )
this procedure work for ternary search int tsearch(int *a,int i,int j,int k) { int m1,m2,len; len = j - i + 1 ; m1=i + (int)floor((float)(len))/3; m2=i + (int)ceil((float)(len))/3; if(k==a[m1]) { printf("\nno found at %d",m1); return m1; } else if(k==a[m2]) { printf("\nno found at %d",m2); return m2; } if(len!= 0) { if(k<a[m1]) return(tsearch(a,i,m1-1,k)); if(k>a[m2]) return(tsearch(a,m2+1,j,k)); } else return -1 ; }
because 3>2>1 ? Other than that, depends on what m1,m2 and m3 represent.