(m-2)/(m+2) * m/(m-1) = [(m-2)*m]/[(m+2)*(m-1)] = (m2 - 2m)/m2 + m - 2)
Horizontal lines have a slope of zero, and the slope of vertical lines is undefined. Parallel lines have equal slopes, and perpendicular lines have slopes that are negative reciprocals of each other. So we can say that: Two nonvertical lines are parallel if and only if they have the same slope. Two lines are perpendicular if and only if their slopes are negative reciprocals of each other. That is, if the slopes are m1 and m2, then: m1 = - 1/m2 or (m1)(m2) = -1
A M1 license allows you to operate any 2-wheel motorcycle or motor-driven cycle, including those 150cc or higher. A M2 license allows you to operate any motorized bicycle, moped, or any bicycle with an attached motor, up to 150cc
y = x2 + 2mx + n complete the square y + m2 = x2 + 2mx + m2 + n = (x + m)2 + n (x + m)2 = y + m2 - n x + m = √(y + m2 - n) x = -m + √(y + m2 - n)
Area = base * height = 5*(4a + b) m2 = (20a + 5b) m2
About 167.2 m2
What is the difference between M1 and M2?
If the slopes are m1 and m2 then m1*m2 = -1 or m2 = -1/m1.
M1 is what is outside the banking system: Your cash, coins, your checking account. M2 is: All of M1 plus, savings accounts, money in banks, small time deposits...etc .
if(m1>m2) f=m1; s=(m2>m3)?m1!m3 what its meaning of this?
M1 money is transaction money, It includes: Coins of all denominations, Paper money including all types of notes, Checking accounts and Traveler's checks. M2 money is M1 money plus Close substitutes ( savings accounts/deposits).
weight, w = G * m1 * m2 / r^2, where G = the universal gravitational constant, m1 = the mass of the object, m2 = the mass of the earth, and r = the separation between the center of gravity of the object and that of the earth. w1 = G * m1 * m2 /(r1^2) -- > the weight when r = r1 w2 = G * m1 * m2 /(r2^2) -- > the weight when r = r2 Given: r2 = 4 * r1 w2 = G * m1 * m2 /(16 r1^2) = w1 / 16 Hence, the object will be 16 times lighter when it is situated 4 times farther away.
*Edit* M2 can print a box of paper in 3x plus 20 hours.
The force, written as an equation, is:F = G (m1)(m2) / r2, whereF is the Force between the massesG is the gravitational constant (~= 6.674 x 10-11 N m2/kg2)m1 is one of the massesm2 is the other massr is the distance between the masses (center to center)Take the formula, and solve for r (I'll show the steps): Fold = G (m1)(m2) / r2.(r2)(Fold)= G (m1)(m2)(r2)= G (m1)(m2) / (Fold)r= √ [ G (m1)(m2) / (Fold) ]Plug the formula into itself, but remember, r = 3r (it tripled).Fnew= G (m1)(m2) / (3r)2.Fnew= G (m1)(m2) /(3√ [ G (m1)(m2) / (Fold) ])2.Fnew=G (m1)(m2)/(32G (m1)(m2) / (Fold) )
this procedure work for ternary search int tsearch(int *a,int i,int j,int k) { int m1,m2,len; len = j - i + 1 ; m1=i + (int)floor((float)(len))/3; m2=i + (int)ceil((float)(len))/3; if(k==a[m1]) { printf("\nno found at %d",m1); return m1; } else if(k==a[m2]) { printf("\nno found at %d",m2); return m2; } if(len!= 0) { if(k<a[m1]) return(tsearch(a,i,m1-1,k)); if(k>a[m2]) return(tsearch(a,m2+1,j,k)); } else return -1 ; }
The velocities of the two bodies after the elastic collisions are given by V1=(M1-M2)U1/(M1+M2)+2M2U2/(M1+M2) V2=(M2-M1)U2/(M1+M2)+2U1M1/(M1+M2) Where, V1,V2 are the velocities of the two bodies after collision. U1,U2 are the velocities of the two bodies before colision.(U1>U2) M1,M2 are the masses of the two bodies. when the mass of two bodies are equal that is M1= M2 then V1=0+2MU2/2M=U2 V2=0+2MU1/2M=U1 Thus when two billiard balls of equal masses undergo perfectly elastic collision the velocities the two bodies are interchanged after the collision.
because 3>2>1 ? Other than that, depends on what m1,m2 and m3 represent.
The force of gravity is F=G*m1*m2/r^2 G is the universal gravitation constant 6.67*10^-11 m^3kg^-1s^-2 m1, m2 are the masses of the two objects, r is the separation. The force on m1 acts in the direction of m2, and the force on m2 acts in the direction of m1.