If: x+7-4x+1 = -10 Then: 8-3x = -10 And: -3x = -10-8 => -3x = -18 So: x = -18/-3 => x = 6
It is negative 3x^2.
x^2 + 3x + 2/(-3x) - x^2 - 2=3x-2+2/(-3x)=3x-2-2/(3x)
3x+12=x+48: 3x-x=-12+48 2x=36 x=18
3x
x is negative 1x is negative 2
-3x + 5 = 20 -3x = 15 x = -5
negative 15
Let square = [x] -4+3*(-2)*[-4]+[3x-2x]=-4-6-2+[x]=-12+[x]The answer is negative 12 plus squared x.
5x^2 + 6x + 9 + (?) = -x^2 +3x + 3 (?) = -5x^2 -6x - 9 -x^2 +3x + 3 = -6x^2 -3x -6 Ans: -6x squared +3x -6
2x + x = -27 3x = -27 3x/3 = -27/3 x = -9
3x + 7 = -3x 6x = -7 x = -7/6
If: x+7-4x+1 = -10 Then: 8-3x = -10 And: -3x = -10-8 => -3x = -18 So: x = -18/-3 => x = 6
It is negative 3x^2.
3x + x + 10 + x = 5x + 10
x = 15
(x - 4) + (2x - 7) = 3x - 11 You get that by: Adding the x terms (one plus two) to get 3x; and adding the plain (non-x) numbers together. In this can both plain numbers are negative, so you get a negative of eleven, which is the sum of the absolute values 4 and 7.