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A point whose y-coordinate is 6 lies on the line whose equation is y equals 5x - 4 What is the x-coordinate of the point?
y = 5x - 4 Substitute 6 in for y; then solve for x: 6 = 5x -4 10 = 5x 2 = x So, the x-coordinate is 2.
How do you find the slope intercept form when the slope is zero and you are given the coordinates 6 and 5?
Assuming 6 is the x-coordinate and 5 is the y-coordinate, you plot your first point at (6,5). From the (0,0) point, you go to the right 6 units, and then up 5 units. Put a dot there. A line with a 0 slope is a horizontal line, so you just draw that line through the point (6,5). The line would look the same regardless of what x value is named in your equation. The equation would read y=5, because the x-coordinate is not used in slope-intercept form (y=mx+b).
What quadrant is a point that has a negative x coordinate and a negative y coordinate is located in?
The quadrant where a point has a negative x coordinate and a negative y coordinate is located in quadrant 3.
How do you determine what's plotted on x-axis and what is plotted on y-axis?
You know which is the x coordinate and which is the y coordinate because (x,y) is an ordered pair. The x is always first and the y second. For example, the point (4,5) has x coordinate of 4 and y of 5.
What is true about every point on a x-axis on a coordinate plane?
Its y-coordinate is zero.
