If the rectangle has a width of x inches, and a length of x + 16 inches, then its perimeter equals to 2x + 2x + 32 or 4x + 32. If x = 14, then x + 16 = 30. So the perimeter of rectangle becomes 2(14) + 2(30) = 28 + 60 = 88 inches.
-6y + 14 + 4y = 32-2y = 32 - 14-2y = 18y = - 9
It works out that: z = -32
32+32+32+32= 128. line them up on top of each other. then, add the last numbers(the 1's places) (the 2's) and then you add the 3's (first numbers) (the 10's place) and then...WALAH!! 128!!
Y=5
2x+32 = 1 2x = 1-32 2x = -31 x = -15.5
I am having difficulty understanding your question. 12 + 20 = 10 is obviously false (12 + 20 = 32).If 4x + 14 = 2x + 30, then x must equal 8.
If the rectangle has a width of x inches, and a length of x + 16 inches, then its perimeter equals to 2x + 2x + 32 or 4x + 32. If x = 14, then x + 16 = 30. So the perimeter of rectangle becomes 2(14) + 2(30) = 28 + 60 = 88 inches.
2x plus 6y equals 32 32 divided by 6= 5 R2 5+2= 7x6= 42-5=37-2=35 so X=5
2x + 4 = 362x = 36 - 42x = 32x = 32/2X = 16
-14
-6y + 14 + 4y = 32-2y = 32 - 14-2y = 18y = - 9
p + 32
46
Given .........................................4x+11-2x+13=32 Combine like terms ....................2x+24=32 Subtract 24 from both sides ......2x=8 Divide both sides by 2 ...............x=4
-6x-32 = 2x -6x-2x = 32 -8x = 32 x = -4
4x+32=-4x+16x4x+32=12x-4x -4x32=8x/8 /84=x