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1) 21 2) 1 3) -25 4) mean= 81, median=84.5 Final answer= 15730
The factors of 81 are 1, 3, 9, 27, and 81. The factor pairs of 81 are 1 x 81, 3 x 27, and 9 x 9. The proper factors of 81 are 1, 3, 9, and 27, or if the definition you are using excludes 1, they are 3, 9, and 27. The prime factors of 81 are 3, 3, 3, and 3. Note: There is repetition of these factors, so if the prime factors are being listed instead of the prime factorization, usually only the distinct prime factors are listed. The distinct prime factor of 81 is 3. The prime factorization of 81 is 3 x 3 x 3 x 3 or in exponential form 34. 81 = 3*3*3*3 or 3^4.
3 3 1
Algebra is the basis of maths you can use it to solve unknown terms such as x. For example: 3x - 3 = 0 3x = 3 x = 1
3^(-4) = (1/3)^4 = 1/81
we(blank)need(blank)to(blank)find (blank)more(blank)hours(blank)for (blank)our(blank)shelves(blank) (Exponents and Exponential Functions: Simplifying Products of Monomials. Punchline Algebra Book B. 11.9) D: x^3 E: 1/x^3 and so on...
Fill in all the blanks in numerical order using 1-81. So like 1 blank 2 3
The multiples of 81 are infinite. The factors of 81 are: 1, 3, 9, 27, 81.
1) 21 2) 1 3) -25 4) mean= 81, median=84.5 Final answer= 15730
1, 3, 9, 27, 81. 1 x 81 = 81, 3 x 27 = 81, 9 x 9 = 81.
The answer is 1,3,9,27,81. 81*1=81 3*27=81 9*9=81 27*3=81 81*1=81
81= 1, 2,9, and 81 27= 1, 3,9, and 27
1/(34) or 1/81 The negative sign means bring the 3 to the denominator (bottom) The 4 travels with the 3 34 is 81
1/3 ^4 = 1/3*1/3*1/3*1/3 = 1/3^4 = 1/81 The answer is 1/81.
1, 3, 9, 27, 81, -1, -3, -9, -27, -81
1, 3, 9, 27, 81
No, algebra 1 is defiantly not the same as math course 3.