7x + 16 = 3x + 4 4x = -12 x = -3
7x+3=10 7x=7 {subtract 3 from each side} x=1 {divide each side by 7}
2x+3=9x 3=9x-2x 3=7x x=3/7
8x-1 = 7x+2 Add 1 to both sides: 8x = 7x+3 Subtract 7x from both sides: 1x = 3 ie x = 3
x2+7x=-2x2+6 3x2+7x-6=0 (3x-2)(x+3)=0 3x-2=0 or x+3=0 x=2/3 or x=-3
x=4
7x + 5y 7(3) + 5(2) 21 + 10 = 31
-7x - 2y = -3
The answer to the math problem -3 7x plus 7 is x equals 1/3.
3+3x+7x=13 3x+7x=10 10x=10 x=1
Subtract by 7x and divide by 2.
4x+9 = 7x+3 4x-7x = 3-9 -3x = -6 x = 2
7x + y + 3 = y7x + 3 = 07x = -3x = -3/7
7x + 8 = 11x + 3, solve for xsubtract 7x from both sides8 = 11x - 7x + 38 = 5x + 3subtract 3 from both sides5 = 5xdivide both sides by 51 = x.
7x+7=28x 28x-7x=7 21x=7 x=3
X = -3
Why not? The statement is trivially true, meaning it holds for all values of x.