There can be no answer because a number sequence, in itself, is not a question.
n4 - n2 or n2(n2 - 1) 14 - 12 = 1 - 1 = 0 24 - 22 = 16 - 4 = 12 34 - 32 = 81 - 9 = 72.......and so on.
The sum of the numbers is 240. If one number is 5 times as big as the other then 240 must be divided by 6. 240/6 = 40. The smaller number must be this while the larger number is 5 times the size. Small number = 40 Larger number = 40 * 5 = 200
x/3=x/8-10/1 find the common denominator which is 24 8x/24=3x/24-240/24 put the numirator in a equation 8x=3x-240 do 8x-5x 5x=-240 divide it by 5 x=-48
1
240 is half-way in between 0 and 480.
n4 - n2 or n2(n2 - 1) 14 - 12 = 1 - 1 = 0 24 - 22 = 16 - 4 = 12 34 - 32 = 81 - 9 = 72.......and so on.
240
19660
19660
- 94/5 + 915/16 + 94/15 = -49/5 + 159/16 + 139/15 = -2352/240 + 2385/240 + 2224/240 = 2257/240 = 997/240
t(n) = 65n2 - 355n + 720 where n = 1, 2, 3, ...
552 The sequence is Un = (125n6 - 3131n5 + 31065n4 - 154445n3 + 399010n2 - 496304n + 228480)/240 for n = 1, 2, 3, ...
240 000 000
240 is a rational number
3.5 percent of 240 = 8.43.5% of 240= 3.5% * 240= 0.035 * 240= 8.4
240/5 = 48 which is a whole number
All multiples of 240 (which are infinite) are evenly divisible by 240.