10 inches
In a short time interval its pi * r2 = pi * 64 = 201 in2. In a longer time interval there is no such thing as a 16 inch pizza because it would be rapidly eaten.
1 12 inch pizza for 9.99 is the better deal. Whether or not we consider the total volume of pizza purchased or just the surface area of pizza (which reflects how much topping there will be) the proportion between the 12 inch and the two 8 inch pizzas (combined) always results in 9:8. So you are getting slightly more pizza with the 12 inch pizza, and it is cheaper, so it is the better deal. Volume = pi * r2 * h. As r2 for the 12 inch pizza = 62 = 36, this is more than 2 * 42 = 32 by the proportion 36:32, which simplifies to 9:8.
No because there are about 64 square inches in the 9 inch pizza and about 254 square inches in the 18 inch pizza.
2
Area of a 14 inch pizza = 43.98in2. Area of a 12 inch pizza = 37.70in2. Difference between the two = 6.28in2.
The weight of a 10-inch pizza can vary depending on the thickness and toppings, but on average, a 10-inch pizza weighs around 10-12 ounces.
10 inches
25 square inches
No Side by side the total would be 20 inches but there would be a space at top and bottom Assuming they are the same depth, then the comparison is between the areas. As the lengths are in the ratio of 10:20 = 1:2, their areas are in the ratio 1²:2² = 1:4 Thus the 20 inch pizza has four times the area of a 10 in pizza, ie a 20 inch pizza is the same as FOUR 10 inch pizzas.
25 square inches.
Assume both pizzas are cut into eight slices. 3 slices of the 12 inch pizza make an angle of3 pi/4 and area is 1/2 radius squared times angle where radius is 6 inch so area = 42.4 sq in 2 slices of the 16 inch pizza make an angle of pi/2 and area is 1/2 radius squared times angle where radius is 8 inch so area = 50.2 sq in so the two 16 inch slices give you more pizza
225 square inches
The 18" refers to the width (diameter) of the pizza.
It is approximately 10 inches in diameter.
It's about 10 inches and cut into 8 slices
The area of the pizza inceases as the square of the radius (or diameter). Assuming the thickness remains the same, then the volume also increases as the square of the radius. So, double radius implies quadruple area implies quadruple cost.