The average of the numbers 148, 99, and 119 is 122.
The factors of 148 are 1, 2, 4, 37, 74, 148 For them to be common, they need to be compared to another set of factors. If you meant 14 and 8, they are 1 and 2.
All integers are RATIONAL, since they can be written as a fraction with denominator 1; in this case: -148 / 1.
rhombus, parallelogram and an isosceles trapezoid
One way to do this would be to assume that four the numbers are 10 (this guarantees that the median is 10.) Now all that is left is to find the fifth number that would make the mean to be 14. We need the average of the numbers to be 14, so we can write the equation: (10 + 10 +10 + 10 + x)/5 = 14where x is the number we need to find. The equation can be simplified:(40 + x)/5 = 148 + x/5 = 14x/5 = 6x = 30.So one possible set of numbers is {10, 10, 10, 10, 30}.(There are many other possible sets as well.)
148
To find the average of a set of numbers, you add all the numbers together and then divide by the total number of values. In this case, the sum of 124, 148, 207, and 21 is 500. Since there are 4 numbers in the set, you divide 500 by 4 to get an average of 125.
The numbers are 148, 150 and 152.
The composite factors of 148 are 4, 74, 148
Pastor Mike Online - 2011 119 Ministries 1-148 was released on: USA: 28 February 2013
They are: 146+147+148 = 441
the average number - add all the numbers together - divide by how many numbers there are and you find the mean. 24,35,62,27 =148 148 divided by 4 = 37 - which is your mean
First, sort the sample. Now, since the sample size is even calculate the average of the middle two elements, 148 and 150, as the median.
The average of 148 and 39 is the sum of 148 and 39 divided by 2, or 187/2, or 93.5
There are an infinite amount of numbers between 148 and 151.The number that's exactly in the middle, equal distances away from both of them,is called the "average" of 148 and 151.It's 149.5
68+84=148 ------> 148/2=74 74 is the average.
They are 59+89 = 148
2,4,37,74