Q: What is the coefficient of the term 13a in the expression 13a plus 6b?

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Re-ordering it : 13a - a -15b + 2b = 12a - 13b

Combine like terms, adding/subtracting the coefficients: (5a² + 6a + 2) + (7a² - 7a + 5) = (5+7)a² + (6-7)a + (2+5) = 12a² - a + 7 (5a² + 6a + 2) - (7a² - 7a + 5) = (5a² + 6a + 2) + (-7a² + 7a - 5) = (5-7)a² + (6+7)a + (2-5) = -2a² + 13a - 3

Let the two digits be represented by a and b. a x b = 12 then, b = 12/a. a + b = 13.........after substituting for b this becomes :- a + 12/a = 13.....multiply throughout by a :- a2 + 12 = 13a....re-arrange :- a2 - 13a + 12 = 0 This factors as (a - 12)(a - 1) = 0 When a - 12 = 0 then a = 12 When a - 1 = 0 then a =1 As we have already substituted for b then b can take one of theses values and the two numbers are 1 and 12. Note : The solution can be easily determined from the values supplied in the question but the process of finding the answer will apply to any such problem.

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13a

13a

Re-ordering it : 13a - a -15b + 2b = 12a - 13b

13a - 6 + a = 5a + 3 + 3a 13a + a - 5a - 3a = 3 + 6 6a = 9 6a/6 = 9/6 a = 3/2

2a2 - 13a + 15 = (2a - 3) (a - 5)

6a^2 - 6ab + 7a^2 = 13a^2 - 6ab = a * (13a - 6b)

You combine like terms so... 13a+12=54. Subtract 2 from both sides and you get 13a=52 . Then divide both sides by 13 and you get 4.. (:

8a4+27a2-15a. contact at saqibahmad81@yahoo.com

a2 - 13a + 22 You're looking for factors of 22 that add up to 13. (a - 2)(a - 11) a = 2, 11

9a + 4a = 26 13a = 26 a = 26/13 a = 2

If the number is A then 3A + 10(A + 4) = 170 3A + 10A + 40 = 170 13A + 40 = 170 13A = 170 - 40 = 130 13A/13 = 130/13 A = 10 Check: 30 + 10(10 + 4) = 30 + 100 + 40 = 170

Yes provided the adaptor, or the plug that is plugged in, has a 13A fuse.