14
Re-ordering it : 13a - a -15b + 2b = 12a - 13b
Combine like terms, adding/subtracting the coefficients: (5a² + 6a + 2) + (7a² - 7a + 5) = (5+7)a² + (6-7)a + (2+5) = 12a² - a + 7 (5a² + 6a + 2) - (7a² - 7a + 5) = (5a² + 6a + 2) + (-7a² + 7a - 5) = (5-7)a² + (6+7)a + (2-5) = -2a² + 13a - 3
Let the two digits be represented by a and b. a x b = 12 then, b = 12/a. a + b = 13.........after substituting for b this becomes :- a + 12/a = 13.....multiply throughout by a :- a2 + 12 = 13a....re-arrange :- a2 - 13a + 12 = 0 This factors as (a - 12)(a - 1) = 0 When a - 12 = 0 then a = 12 When a - 1 = 0 then a =1 As we have already substituted for b then b can take one of theses values and the two numbers are 1 and 12. Note : The solution can be easily determined from the values supplied in the question but the process of finding the answer will apply to any such problem.
13a
To simplify the expression 6a^2 - 6ab + 7a^2, first combine like terms. Combine the terms with the same variable (a) raised to the same power. This results in 13a^2 - 6ab as the simplified expression. Remember to keep the terms in standard form with the variable term first, followed by any constant terms.
13a
Re-ordering it : 13a - a -15b + 2b = 12a - 13b
13a - 6 + a = 5a + 3 + 3a 13a + a - 5a - 3a = 3 + 6 6a = 9 6a/6 = 9/6 a = 3/2
2a2 - 13a + 15 = (2a - 3) (a - 5)
You combine like terms so... 13a+12=54. Subtract 2 from both sides and you get 13a=52 . Then divide both sides by 13 and you get 4.. (:
8a4+27a2-15a. contact at saqibahmad81@yahoo.com
a2 - 13a + 22 You're looking for factors of 22 that add up to 13. (a - 2)(a - 11) a = 2, 11
9a + 4a = 26 13a = 26 a = 26/13 a = 2
If the number is A then 3A + 10(A + 4) = 170 3A + 10A + 40 = 170 13A + 40 = 170 13A = 170 - 40 = 130 13A/13 = 130/13 A = 10 Check: 30 + 10(10 + 4) = 30 + 100 + 40 = 170
Yes provided the adaptor, or the plug that is plugged in, has a 13A fuse.