Fe3+ + 3OH- _____> Fe(OH)3
To write a balanced equation for the reaction between FeCl3 and Na2S, first determine the chemical formula for the products formed when they react. In this case, the products are Fe2S3 and NaCl. Then, write the balanced chemical equation by ensuring that the number of atoms of each element is the same on both sides of the equation. The balanced equation for FeCl3 + Na2S is 2FeCl3 + 3Na2S -> Fe2S3 + 6NaCl.
The balanced equation for the reaction of iron with chlorine is: Fe + Cl2 -> FeCl3.
When ferric chloride (FeCl3) is mixed with iron (Fe), the iron displaces the chloride ion to form ferrous chloride (FeCl2) and iron chloride (FeCl3). The chemical equation is: FeCl3 + Fe -> FeCl2 + FeCl3.
The general reaction type between FeCl3 and NaOH is a double displacement reaction. This reaction results in the formation of Fe(OH)3, a precipitate, and NaCl, which remains in solution.
The reaction between benzoic acid (C6H5COOH) and ferric chloride (FeCl3) forms a complex between the iron ion and the oxygen atom of the carboxyl group. The general equation for this reaction is C6H5COOH + FeCl3 → [Fe(C6H5COO)3] + 3HCl.
The balanced equation for the reaction between phenol (C6H5OH), sodium hydroxide (NaOH), and iron(III) chloride (FeCl3) is: C6H5OH + NaOH + FeCl3 → C6H4(OH)Na + FeCl2 + H2O
The balanced full molecular equation for this reaction is: 2FeBr3(aq) + 3Cl2(g) -> 2FeCl3(aq) + 3Br2(l)
FeCl3 + 6KSCN --> [Fe(SCN)6]-3 + 6K+ + 3Cl- This is a complex ion equation. K has a charge of +1 and Cl has a charge of -1 but since these form an aqueous solution, they are seperated. Put together, the equation cannot be balanced.
When iron (Fe) reacts with chlorine gas (Cl2), they form iron (III) chloride (FeCl3) according to the equation: 2 Fe + 3 Cl2 → 2 FeCl3. This reaction is a redox reaction where iron is oxidized and chlorine is reduced.
Combining iron(III) chloride solution (FeCl3) with sodium phosphate solution (Na3PO4) will precipitate iron(III) phosphate (FePO4). This reaction can be represented as: FeCl3(aq) + Na3PO4(aq) → FePO4(s) + 3NaCl(aq)
The amount of FeCl3 needed depends on the concentration of the FeCl3 solution required for the test. Typically, a 2-5% solution of FeCl3 is used. To make a 100mL of 2-5% FeCl3 solution, you would need to dissolve 2-5 grams of FeCl3 in distilled water. The exact amount can be calculated using the formula: (desired % concentration/100) x volume of solution needed x molar mass of FeCl3.
Ferric Chloride = FeCl3Ammonium Hydroxide = NH4OHFerric (III) Chloride + Ammonium Hydroxide = Ferric (III) Hydroxide + Ammonium Chloride FeCl3 + 3NH4OH = Fe(OH)3 + 3NH4Cl