Best Answer

Don't see any "following" and this I's guessing is what you want?

113-(-68)^.5 =

113-((-1)(68))^.5 =

113-(68)^.5 (-1)^.5 =

113-i(68)^.5

Q: What is the correct notation for the complex number 113-square root-68?

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The correct scientific notation for 0.000681 is: 6.81 × 10-4

Yes. This can be verified by using a "generic" complex number, and multiplying it by its conjugate: (a + bi)(a - bi) = a2 -abi + abi + b2i2 = a2 - b2 Alternative proof: I'm going to use the * notation for complex conjugate. Any complex number w is real if and only if w=w*. Let z be a complex number. Let w = zz*. We want to prove that w*=w. This is what we get: w* = (zz*)* = z*z** (for any u and v, (uv)* = u* v*) = z*z = w

You can turn a number into scientific notation, but not an operation.

A number such as this would not normally be expressed in scientific notation.

The way you wrote it is the standard notation. Standard notation means to write the number in its standard form. So, a number such as 150 is simply written as 150 in standard notation. The same applies to decimals.

Related questions

113 is not a complex number and so there cannot be any correct notation.

-81-14 is not a complex number. And its square is 9025.

113-2i sqr 17

The correct scientific notation for 0.000681 is: 6.81 × 10-4

500.0 in Scientific Notation = 5 x 102

It is 1345.

5 x 103.

192

The base number must be 10.

0.99 in Scientific Notation = 9.9 x 10-1

A complex number a + bi, can be represented as a 2x2 matrix: [a -b] [b a ] or [a b ] [-b a ] , just keep the same notation throughout your work. See the wikipedia article on Complex Numbers, and the related link for some more information.

The given number has a significand of 18. In scientific notation, the significand must lie in the interval [1, 10). So the correct notation is 1.8*107