Wiki User
∙ 12y agoDon't see any "following" and this I's guessing is what you want?
113-(-68)^.5 =
113-((-1)(68))^.5 =
113-(68)^.5 (-1)^.5 =
113-i(68)^.5
Wiki User
∙ 12y agoThe correct scientific notation for 0.000681 is: 6.81 × 10-4
Yes. This can be verified by using a "generic" complex number, and multiplying it by its conjugate: (a + bi)(a - bi) = a2 -abi + abi + b2i2 = a2 - b2 Alternative proof: I'm going to use the * notation for complex conjugate. Any complex number w is real if and only if w=w*. Let z be a complex number. Let w = zz*. We want to prove that w*=w. This is what we get: w* = (zz*)* = z*z** (for any u and v, (uv)* = u* v*) = z*z = w
You can turn a number into scientific notation, but not an operation.
The way you wrote it is the standard notation. Standard notation means to write the number in its standard form. So, a number such as 150 is simply written as 150 in standard notation. The same applies to decimals.
A number such as this would not normally be expressed in scientific notation.
113 is not a complex number and so there cannot be any correct notation.
-81-14 is not a complex number. And its square is 9025.
113-2i sqr 17
The correct scientific notation for 0.000681 is: 6.81 × 10-4
500.0 in Scientific Notation = 5 x 102
The correct scientific notation for the number 0.99 is 9.9 x 10^-1.
It is 1345.
5 x 103.
192
The base number must be 10.
The given number has a significand of 18. In scientific notation, the significand must lie in the interval [1, 10). So the correct notation is 1.8*107
A complex number a + bi, can be represented as a 2x2 matrix: [a -b] [b a ] or [a b ] [-b a ] , just keep the same notation throughout your work. See the wikipedia article on Complex Numbers, and the related link for some more information.