(24/6)3 = 43 = 64
6 x 2^2 = 6 x 4 = 24 cm^3
To find the total surface area of the 3-cube tower, we need to calculate the surface area of each cube individually and then add them together. The surface area of a cube is given by 6 times the side length squared. For the 3-inch cube: 6 * 3^2 = 54 square inches For the 2-inch cube: 6 * 2^2 = 24 square inches For the 1-inch cube: 6 * 1^2 = 6 square inches Adding these together: 54 + 24 + 6 = 84 square inches Therefore, the total surface area of the 3-cube tower is 84 square inches.
It is: 6*2*2 = 24 square m
A cube has 6 sides all of the sides are squares. And a cube also has 12 edges.
(24/6)3 = 43 = 64
24/6 = 4 and 24/4 = 6, therefore 24 divided by 4 is the bigger quotient.
(7/6)3 = 1.5880 (approx).
-28
3/24 + 6
168
0.5416 The 6 is overlined.
24/6 = 4
It is 24/4 = 6
A cube has 24 corners and 6 faces.
24.5
24