radius = 7.170724462 cm so diameter will = 14.341448924 cm
Check:-
Volume = pi*7.1707244622*13 = 2100 cubic cm
You put 2100 in your caculator then push the button that look like a cheak mark or a v with a little line.
511 and 2100
700 gal/ 20 min = 35 gallons/ 1 min * 60 min/ 1 hour= 2100 gallons per hour.
The first twelve positive integer multiples of 300 are as follows: 1 x 300 = 300 2 x 300 = 600 3 x 300 = 900 4 x 300 = 1200 5 x 300 = 1500 6 x 300 = 1800 7 x 300 = 2100 8 x 300 = 2400 9 x 300 = 2700 10 x 300 = 3000
6k meaning 6 kilometers = 6000 meters. 35 minutes = 60 (sec/min) * 35 min = 2100 sec, then add 30 sec = 2130 sec 6000 m / 2130 sec = 2.8169 m/s 1 m/s is 2.2369 miles per hour. So 2.8169 m/s * 2.2369 [MPH/(m/s)]= 6.3011 MPH
I presume the tunnel has an arch shaped cross-section with a semicircle on top of a rectangle. In this case the volume of the tunnel is the volume of the cuboid bottom plus the volume of half cylinder which forms the top. The volume of the half cylindrical top is ½πr²h = ½ × π × (6m)² × 25m = 450π m³ The volume of the cuboid is length × width × height. The length is 25m. The width is the diameter of the top half cylinder which is twice the radius at 2 x 6m = 12 m. The height is not clear. I am going to presume it is to the top of the arch, so that the height of the cuboid is the height less the radius of the cylinder, namely 7m - 6m = 1m. Thus the volume of the cuboid bit is 25m x 12m x 1m = 300 m³ Thus the volume of the tunnel as a whole is 300 m³ + 450π m³ ≈ 1713.72 m³ (If the 7m height refers to the height of the vertical walls, then the volume of the cuboid is 25m x 12m x 7m = 2100 m³ and the volume of the tunnel is 2100 m³ + 450π m³ ≈ 3513.72 m³.)
Volume is determined by multiplying the height by the width and then the depth. This would give you 2100 cubic centimeters.
According to Russell Kightley, it is 2100 nanometers in length, and 700 nanometers in diameter.
About 2997.279 MPH. (IF your taking a 20' RADIUS.) If you are talking of a 20' diameter. then would be feet/minute = rpm * diameter * pi 131946.891468 feet/minute
From Wikipedia: "...between 1800 and 2100 solar radii..." Note that this means the radius is not known precisely. Assuming 1800 solar radii. Also, the Sun has 109 times the radius (or diameter) of Earth. That results in this star having 1800 x 109 = about 200,000 times Earth's diameter. Take the cube of that, and you get a volume that is 7,500,000,000,000,000 (7.5 x 1015) times that of Earth. With the higher number (2100), you get 12,000,000,000,000,000 (12 x 1015). A few other sources say it is closer to 11,666,192,832,000,000 Earths!
7% of 2100 = 7% * 2100 = 0.07 * 2100 = 147
ANSWER: 1055% of 2100= 5% * 2100= 0.05 * 2100= 105
80% of 2100 = 80% * 2100 = 0.8 * 2100 = 1680
The largest star is VY Canis Majoris: It has a diameter of 1.55-1.86 billion mi. or 1800- 2100 times that of the sun.
2100
2100
There is no next number because numbers are infinitely dense. The next positive integer is 2100.