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What is the equation of a circle whose diameter's end points are at 2 -3 and 8 7?
Wiki User
∙ 6y ago
The mid point of the diameter is the circle's centre:
Mid point of (2, -3) and (8, 7) is ((2 + 8)/2, (-3 + 7)/2) = (5, 2)
The radius is half the diameter, but as the equation for a circle requires the radius squared:
radius = diameter/2
→ radius² = diameter² / 4
Diameter (and diameter²) can be found using Pythagoras:
diameter² = change_in_x² + change_in_y²
= (8 - 2)² + (7 - -3)²
= 6² + 10²
= 136
→ radius² = 136/4 = 34
Circle with centre (X, Y) and radius r has equation:
(x - X)² + (y - Y)² = r²
→ (x - 5)² + (y - 2)² = 34
→ x² -10x + 25 + y² - 4y + 4 = 34
→ x² + y² - 10x - 4x - 5 = 0
Wiki User
∙ 6y ago
Wiki User
∙ 6y agoIt is (x - 5)2 + (y - 2)2 = 34
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What is the equation of a circle whose center is at the origin and whose radius is 10?
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What is the equation of a circle whose diameter end points are at 10 -4 and 2 2 on the Cartesian plane?
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The inscribed polygon this is the correct answer trust me thank you love someone
What is polygon whose vertices are on a circle and whose other points are inside the circle?
The inscribed polygon this is the correct answer trust me thank you love someone
What is a polygon whose vertices are on the circle and whose other points are inside a circle?
The inscribed polygon this is the correct answer trust me thank you love someone
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