7 to the second power
The base and exponent form a pair. You can chose any positive base and that will determine the exponent.243 = 49^1.5 that is base = 49, exponent = 1.5)or 243 = 10^2.5353 (approx) or 243 = 7^3.
The two are related. The answer could be base 2, exponent 18 or base 8, exponent 6 or base 10, exponent 5.4185 or base 262144, exponent 1 or base 68,719,476,736 and exponent 0.5
Yes, you can, but it starts getting complicated. You can, for example have a number raised to an exponent that is itself a number raised to an exponent, or you can have a number raised to an exponent and the result raised to another exponent.
yes it can if the exponent is 1.
The base could be 11 and the exponent 2, giving 112 But, it could equally be base = 14641, and exponent = 0.5, or base = 10, and exponent = 2.082785 (approx)
72 = 49
72 = 49
It is: 7^2 = 49
It is: 72 = 49
49
To find the sum of (2^4) and (7^2), first calculate each exponent: (2^4 = 16) and (7^2 = 49). Adding these together gives (16 + 49 = 65). Therefore, the sum in standard form is (65).
The base and exponent form a pair. You can chose any positive base and that will determine the exponent.243 = 49^1.5 that is base = 49, exponent = 1.5)or 243 = 10^2.5353 (approx) or 243 = 7^3.
If you mean 7^2 then 2 is the exponent and it means 7*7 = 49
7-2 = 1/72 = 1/49
I think it would be "07". * * * * * No. For exponent = 1 mod 4 the digits are 07 For exponent = 2 mod 4 the digits are 49 For exponent = 3 mod 4 the digits are 43 For exponent = 0 mod 4 the digits are 01 Since 124 = 0 mod 4, the answer is 01
The prime factorization of 49 is 7 x 7. In factor form, this can be written as 7^2, where the exponent indicates the number of times the factor (7) is repeated. Therefore, the factor form repeated of 49 is 7^2.
The exponent.