It can be simplified to: 3a^2 +10a+7 or factored as (3a+7)(a+1)
a3-4a = a(a2-4) when factored
Yes, it is a monomial.
Since a monomial is a term, any real number is is a monomial.
A completely factored form is one which is composed of product of factors and can't be factorized further. Let us consider two examples: x2 - 4x + 4 is not a factored form because it can be factored as (x - 2)(x - 2). (x +1)(x2 - 4x + 4) is also not a factored form because x2 - 4x + 4 can be factored further as (x - 2)(x - 2). So, the completely factored form is (x + 1)(x - 2)(x - 2).
It can be simplified to: 3a^2 +10a+7 or factored as (3a+7)(a+1)
To find the GCF of each pair of monomials of 10a and lza²b, we can use the following steps: Write the complete factorization of each monomial, including the constants and the variables with their exponents. 10a = 2 ⋅ 5 ⋅ a lza²b = lz ⋅ a ⋅ a ⋅ b Identify the common factors in both monomials. These are the factors that appear in both factorizations with the same or lower exponent. The common factors are : a Multiply the common factors to get the GCF. GCF = a Therefore, the GCF of each pair of monomial of 10a and lza²b = a
To find the GCF of each pair of monomial of -8x³ and 10a²b², we can use the following steps: Write the complete factorization of each monomial, including the constants and the variables with their exponents. -8x³ = -1 ⋅ 2 ⋅ 2 ⋅ 2 ⋅ x ⋅ x ⋅ x 10a²b² = 2 ⋅ 5 ⋅ a ⋅ a ⋅ b ⋅ b Identify the common factors in both monomials. These are the factors that appear in both factorizations with the same or lower exponent. The common factors are: 2 Multiply the common factors to get the GCF. GCF = 2 Therefore, the GCF of each pair of monomial of -8x³ and 10a²b² is 2.
The factors of 308 are 1, 2, 4, 7, 11, 14, 22, 28, 44, 77, 154, 308.
This is simply 10a * a * a * a, or 10 * a * a * a * a. (Most people would consider the 10a4 form factored, since expanding it just makes it more complicated here.)
to solve this expression: 10a-4(a+2) -> 10a-4(a)-4(2) -> 10a-4a-8 -> 6a-8
If you mean: 7x+91 then it can be factored to 7(x+13)
To find the GCF of each pair of monomial of 8ab³ and 10a²b², we can use the following steps: Write the complete factorization of each monomial, including the constants and the variables with their exponents. 8ab³ = 2 ⋅ 2 ⋅ 2 ⋅ a ⋅ b ⋅ b ⋅ b 10a²b² = 2 ⋅ 5 ⋅ a ⋅ a ⋅ b ⋅ b Identify the common factors in both monomials. These are the factors that appear in both factorizations with the same or lower exponent. The common factors are: 2, a, and b² Multiply the common factors to get the GCF. GCF = 2 ⋅ a ⋅ b² = 2ab²
12a + 4 - 10a = 2a + 4 or 2*(a + 2)
4
The only common factor of 10a and 5b is a 5. So the factored form will be something like: 5(2a _ b) assuming the _ is filled in with the proper operation (+ - * / etc.). If the original expression is 10a + 5b, the answer would be 5(2a + b).
Monomial. Monomial. Monomial. Monomial.