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Is the coefficient of the square a Prime number?

eg if the equation begins 3a2 then the factors must be (3a +/- x)(a +/- y)

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Q: What is the first thing you should look for when factoring?
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How do you tell if a polynomial cannot be factored?

Try all the factoring techniques that you have been taught. If none work then it is prime (cannot be factored), try looking for (1) a greatest common factor (2) special binomials ... difference of squares, difference (or sum) of cubes (3) trinomal factoring techniques (4) other polymonials look for grouping techniques.


How do you identify a common monomial factor?

Are you talking about factoring a polynomial and doing factorization by pulling a monomial out? If you have an equation that looks like (3x^2 +6yx + 12X^3) You would first look for the coefficient that can go into all of them = 3 in this case then what is a variable you can pull out of all of the in this case =x so you pull out 3x and you get 3x(x+2y+4x^2)


Where should you look for track marks?

near train stations


How do you factor a2 - c2?

To factor this particular expression, just look to see what factors both values share. In this case, 2 is the only factor shared. Using the distributive method, factoring out 2 works like this: a2 - c2 (usually written 2a - 2c) = 2 * (a-c) So the factors are 2 and (a-c).


How could you use the distributive property to check your factoring?

You use the FOIL method, which stands for First Outside Inside Last. Say, for example, you have the factored polynomial (2x - 3)(x + 1). To FOIL it you would take the two first components, 2x and x, and multiply them together, getting 2x^2. Next, you take the two outside components, 2x and 1, and multiply them together, getting 2x. After that, you take the two inside components, -3 and x, and multiply them together, getting -3x. Finally, you take the two last components, -3 and 1, and multiply them together, getting -3. You add all of these things together to get 2x^2 - x - 3. With only variables, you could look at it this way: (ax + b)(x + c), the answer being ax^2 + acx + bx + bc.

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