Two numbers that when added equal 56 and when multiplied equal 783?
X + Y = 56 [therefore] X = 56 - Y
XY = 783 [therefore] (56 - Y)(Y) = 783
56Y - Y^2 = 783
solve for Y, then don't forget to plug Y back into the original
and find "X" (X = 56 - Y ) a+b = 56 AND: ab = 783 substitution: a =
56-b (from addition equation) put this back into the multiplication
equation: (56-b)b = 783 expansion: 56b -b^2 = 783 rearrange: -b^2 +
56b - 783 quadratic formula: b = (-56+sqrt(3136-4(-1)(-783))) / -2
and b = (-56-sqrt(3136-4(-1)(-783))) / -2 b=27 and b=29 from the
addition equation: 56-27 = a=29 56-29 = a =27 it's kind of a
"repeat" question