The digit with the second greatest value in the number is '1'. its value is second to the largest number which is 2.
01337
infinity
The "7" digit had the greatest value because it is in the UNITS column.
1111 + 0001 + 1000 + 0100 = 11100 Remember that in binary, 1 + 1 = 10 (0 carry 1) and 1 + 1 + 1 = 11 (1 carry 1).
0000 0001 0010 0011 0100 0101
It is simplest to convert each hexadecimal digit into its 4-digit binary equivalent. So: 5 = 0101 A = 1010 3 = 0011 4 = 0100 F = 1111 6 = 0101 So, the binary equivalent is 10110100011010011110101.
Write each hexadecimal digit straight into binary: 5 = 0101 4 = 0100 2 = 0010 So 0x542 = 0101 0100 0010 = 10101000010 (without the spaces). Hex digit to binary conversion: 0 = 0000, 1 = 0001, 2 = 0010, 3 = 0011 4 = 0100, 5 = 0101, 6 = 0110, 7 = 0111 8 = 1000, 9 = 1001, a = 1010, b = 1011 c = 1100, d = 1101, e = 1110, f = 1111
A 4 BCD code is a 4 decimal-digit BCD code, thus a 16 digit binary-code. You take the decimal number 3545. It's BCD code is 0011 0101 0100 0101 where every 4 bits represent a decimal digit.
87
1539026015
A 0, 1 system using: 5, 2, 1', 1 instead of 8, 4, 2, 1 to count binary numbers. Example: 0000 0001 0010 0101 0100 0101 1001 1100 1101 1111
What is the product of the binary numbers 0101 and 0101?
1 = 0001 2 = 0010 3 = 0011 4 = 0100 5 = 0101 6 = 0110 7 = 0111 8 = 1000 9 = 1001
-123 = 11 1000 0101 [I presume the number 123 is in decimal] First write the positive number in binary using 10 bits (I've split it into groups of 4 bits to make it easier to read): 123 = 00 0111 1011 Convert to 1s complement by inverting all bits (any 0 => 1, any 1 => 0): 00 0111 1011 => 11 1000 0100 Finally add 1 to get 2s complement: 11 1000 0100 + 1 = 11 1000 0101 Thus the 2s complement of the negative number: -123 = 11 1000 0101 This can also be expressed in hexadecimal: -123 = 0x385 Or in octal (easy to convert if the binary number is first written in groups of 3 bits): -123 = 1 110 000 101 = 01605 [I've used C notation for the hexadecimal and octal numbers.]
The Alphabet in Binary CodeLetterBinary CodeA01000001B01000010C01000011D01000100E01000101F01000110G01000111H01001000I01001001J01001010K01001011L01001100M01001101N01001110O01001111P01010000Q01010001R01010010S01010011T01010100U01010101V01010110W01010111X01011000Y01011001Z01011010LetterBinary Codea01100001b01100010c01100011d01100100e01100101f01100110g01100111h01101000i01101001j01101010k01101011l01101100m01101101n01101110o01101111p01110000q01110001r01110010s01110011t01110100u01110101v01110110w01110111x01111000y01111001z01111010
Add the binary equivalent of 3 (0011) to each digit of the number in binary format. Ex: 1. Excess-3 of 6 is 0110(6) + 0011(3)= 1001(9) 2. Excess-3 of 12 is 0001 0010 + 0011 0011 = 0100 0101 (45)