The digit with the second greatest value in the number is '1'. its value is second to the largest number which is 2.
This is a weekly question posted by Columbus State University. See http://www.colstate.edu/mathcontest/problem.php?CategoryID=3&LinkID=CurrentPlease do not answer this question as this person is too lazy to figure it out themselves.
Select all the numbers that $4221462$ is divisible by.
1 The largest five-digit number is 99999 and the smallest six-digit number is 100000, so the difference is one. If you're just looking for an answer to a homework question, that's all you need. For the brainy: Suppose the answer was greater than one. That would mean that there are one or more numbers between the largest five-digit number and the smallest six-digit number that cannot be written with either five or six digits. Either they would have to be written with four or fewer digits, which would make them smaller than any five-digit number, or with seven or more digits, which would make them larger than any six-digit number. If the answer was less than one, it would mean that it would be possible to have a five digit number that was greater than a six-digit one. So the answer must be one.
To create the largest even number, we should place the highest digit in the most significant place value to maximize its value. The highest digit available is 9, so we should place it in the leftmost position. Following this logic, the largest even number using the given digits is 987654321.
-1
The largest 4 digit number that is divisable by 1 2 3 and 4 is........9996
a 3 digit number that is divisible by on is a three digit number that is a multiple of one.
-1
There is no 4-digit number that is divisible by zero.
There is no limit to the number of digits.If, for example, a X is a k-digit number which is divisible by 4 then 10*X is divisible by 4 and 10*X will be a (k+1)-digit number.
8
to be divisible by 5 the last digit of the number has to be 0 or 5
It is 9.
The first 3 digit number divisible by 19 is 114 (= 19 x 6) The last 3 digit number divisible by 19 is 988 (= 19 x 52) That means that there are 52 - 6 + 1 = 47 three digit numbers that are divisible by 19.
9999 is the largest 4-digit number.When added with 1 it becomes 10000. 9999 + 1 = 10000.
There are 18 numbers with 2 digits that are divisible by 5. First 2 digit number is 10 → 10 ÷ 5 = 2 → first 2 digit number divisible by 25 is 5 × 2 Last 2 digit number is 99 → 99 ÷ 5 = 19 4/5 → last 2 digit number divisible by 5 is 5 × 19 → There are 19 - 2 + 1 = 18 numbers with 2 digit divisible by 5.