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The largest exterior angle measure is 120o. It is the exterior measure of an equilateral triangle (which is a regular polygon).

Q: What is the largest exterior angle that any regular polygon can have?

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A regular polygon with an exterior angle of40O is a nonagon, and has 9 sides.

The sum of the exterior angles of a regular polygon equal 360° . If one such angle measures 36° then the polygon has 360/36 = 10 sides.

exterior angle of regular polygon is always 360 divided by number of sides, so number of sides = 360 divided by exterior angle, in this case 360/32.72 ie 11.

A regular octagon. Since the exterior angle is 45 degrees and the sum of all exterior angles of any polygon is 360 degrees, then 45⁰n = 360⁰ n = 8

Exterior angle of ANY regular n-sided polygon is 360/n degrees, in this case 360/12 ie 30o

Related questions

With a regular polygon: 360/exterior angle = number of sides

360 ________________________________________________ Sum of Interior Angles of a Polygon = 180 (n-2) Sum of Exterior Angles of a Polygon = 360 The sum of an angle and an exterior angle of a regular polygon is 360

160

Exterior angle regular polygon = 360° ÷ number of sides = 360° ÷ W Interior angle regular polygon = 180° - exterior angle regular polygon = 180° - (360° ÷ number of sides ) = 180° - (360° ÷ W)

Each exterior angle of a regular polygon with n sides is 360/n degrees. Each interior angle of a regular polygon is 180 - Exterior angle. A direct formula for the interior angle is 180*(n-2)/n degrees.

360/number of sides = exterior angle

If each exterior angle is 9 degrees then it is a regular 40 sided polygon.

360/number of sides = exterior angle

360/number of sides = exterior angle

Each exterior angle is 15 degrees

Providing that it's a regular polygon then each exterior angle will measure 12 degrees.

If it's a regular polygon then each exterior angle measures 36 degrees