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140 is the obvious upper bound for this question. It is not a solution, however, because it doesn't give zero remainder when divided into 570 or 828. If we work our way down from 140, though, the first number that yields equal remainders is of course the answer. I employed a vaguish and fairly inefficient algorithm to reach the answer, not having come across such a problem before. So I won't attempt to record my method. Suffice it to say that the correct answer was the fifteenth number I tested: 140 = (43x 3) + 11

570 = (43 x 13) + 11

828 = (43 x 19) + 11

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Q: What is the largest integer that gives the same integral remainder when dividing each of the following 3 numbers 140 570 828?
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