If it's a right angle triangle then side ac is 10 units in length.
Suppose ABC is a triangle. There is nothing in the question that requires the triangle to be right angled. Suppose AB is the side opposite to angle C and BC is a side adjacent to angle C. Then AB/BC = sin(C)/sin(A)
yes
False
Each side of the triangle is 16.16581 units in length.
If it's a right angle triangle then side ac is 10 units in length.
Not too sure about the question as there is no triangle pictured at the right. But in general the area of a triangle is 0.5*base*perpendicular height
C = sqrt(C2) C2 = A2 + B2 - 2 A B cos(AB)
Without a type of triangle and the associated angle measurements, an answer is impossible.
Find the length of each sideside ab and bc differ in length by 10cm and the side ac and bc differ in length 3cmfind the lenght of each sideperimeter of a triangle abc is 103cm?
Suppose ABC is a triangle. There is nothing in the question that requires the triangle to be right angled. Suppose AB is the side opposite to angle C and BC is a side adjacent to angle C. Then AB/BC = sin(C)/sin(A)
If it is an isosceles triangle then side BC is 15cm and side AC is 15m
Use Pythagoras' theorem for a right angle triangle to find the length of the 3rd side.
In right triangle ABC, angle C is a right angle, AB = 13and BC = 5 What is the length of AC? Draw the triangle to help visualize the problem.
Use Pythagoras' theorem to find the length of the 3rd side
Assuming you mean side AB is 5: If angle B is the right angle, side AC is the hypotenuse and is of length 6. If angle A is the right angle, side BC is the hypotenuse and is of length sqrt(52 + 62) ~= 7.81 Angle C cannot be the right angle as then side AB would be the hypotenuse but the hypotenuse is the longest side and side AB is shorter than AC.
Perimeter of a triangle = (length of side #1) + (length of side #2) + (length of side #3)