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Firstly I'm assuming that the wheel's diameter is 35cm. If it is not in cm, then you will need to fix the following calculations.

a = v2/r

Calculating the speed of the clay comes to approximately 1.65m/s

Substituting into the formula gives an acceleration of approximately 7.8m/s2

(If you were actually looking for an angular acceleration, you will need to use a different formula)

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Q: What is the magnitude of the acceleration of a speck of clay on the edge of a potter's wheel turning at 45 revolutions per minute if the wheel's diameter is 35?
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