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It is: 180-72 = 108 degrees and it is a regular 5 sided pentagon

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Q: What is the measures of the interior angles of a regular polygon if each exterior angle measures 72 degrees?
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One exterior angle of a regular polygon measures 30 degrees what is the sum of the polygon's interior angle measures?

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What is the sum of the measures of the interior angles of a regular polygon if each exterior angle measures 72 degrees?

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One exterior angle of a regular polygon measures 40 What is the sum of the polygon's interior angle measures?

The sum of a regular polygon's interior angles is always equal to (n-2) * 180, where n is the number of sides in the polygon. Given that one exterior angle measures 40 degrees, we can find the interior angle by subtracting 40 from 180 degrees (since the exterior and interior angles are supplementary) to get 140 degrees. So, the sum of the interior angles of the regular polygon is 140 * n.


What is the measures of the interior angles of a regular polygon if each exterior angle measures 72?

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What is the sum of the measures of the interior angles of a regular polygon if each exterior angle measures 72?

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