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clearly the given series is an arithmetic progression with a common difference of -11,that is every term is obtained by subtracting 11 from the previous term
for any A.P, n-th term is
a(n)=a(1)+ (n-1)d
where a(1)=first term and d=common difference
here a(1)=100, and d= -11
so,
a(n)=100+(n-1)x(-11)
or, a(n)=111-11n
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