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clearly the given series is an arithmetic progression with a common difference of -11,that is every term is obtained by subtracting 11 from the previous term

for any A.P, n-th term is

a(n)=a(1)+ (n-1)d

where a(1)=first term and d=common difference

here a(1)=100, and d= -11

so,

a(n)=100+(n-1)x(-11)

or, a(n)=111-11n

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Q: What is the nth term formula of 100 89 78 67?
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