x = 1, y = 9. Here's one way to solve:
Since y = x + 8, from the second equation, substitute (x + 8) for y in the first equation: x + (x+8) = 10 --> 2x + 8 = 10, and 2x = 2, so x = 1.
Now y = x + 8, so substitute x=1 and get y = 1 + 8 = 9. Check your answer in the first equation: [x+y=10]: 1+9=10, which checks out.
This is a system of equations:-x + 5y = 10-5x + 2y = 27Multiply the first equation by 5.-5x + 25y = 50Subtract the 2 equations:23y = 23Solve:y = 1-x + 5(1) = 10-x = 5x = -5Thus, the ordered pair is (-5, 1).
10-4=6
(10, 2)
6x + 10 + 4x = 5010x + 10 = 5010x = 40x = 4
x = 10
x = 5, y = 1
x = 12, y = 1
If 5x plus 3y equals 13, the x equals 2 and y equals 1. This is because 5x2=10 and 3x1=3, and 10+3=13.
The answer is 144. The compound operator for (a) and (b) in each pair is a * (a+b). For 9 and 7, this is 9 x (9+7) = 9 x 16 = 144.
-4 plus 10 equals 6.
If x equals 10 and y equals 10, then 9x plus 8y equals 170.
x = 3 and y = 4 so the lines intersect at (3, 4)
By listed sequence, it is 5 plus 10 = 15 divided by 5 equals 3. By order of operations, it is 5 + (10/5) = 5 + 2 equals 7.
x = 4 and y = -1 (4. -1)
x=10
12 + 10 + 11 equals 33
-10 plus 10 equals 0.