The perimeter would be 40cm.
The easiest way to reason this is to consider how you could connect nine squares together while leaving the largest amount of perimeter exposed. In other words, what's the largest number of faces you can leave exposed on a set of squares that are all connected? The answer is that if you connect all of the squares in a line, then the two end squares will have three faces exposed and the other seven squares will have two faces exposed. That gives you 2 * 7 * 2cm + 3 * 2 * 2cm = 28cm + 12cm = 40cm. So the maximum perimeter you can get is 40cm. There are many other ways that you can arrange the squares to give you the same perimeter (eg. a plus sign, a zig-zag, and so on), but none that will give you more.
What is a rectangle were the area is 10 and the perimeter
Area of square = 81 cm2 so side of square = 9 cm and then perimeter = 4*side = 36 cm.
Perimeter: 6+8+10 = 24 units
the perimeter of a rectangle with two 5cm squares will be 30cm
The perimeter is four.
4 white squares and 4 black squares on each row
The perimeter would be 40cm.
10x10 Squares...
The perimeter is 24 feet.
Then they both will have the same perimeter
you press all the squares on the second row once then the 2 in the middle on the third row then all on the last row
40
15.49
The back row of squares on a draughts board is called a crown-head.
pyramid with 2 squares on top row, 3 squares on second row, 5 squares on third row, and 7 squars on bottom row