To determine the perimeter of 10 squares in a row, we need to know the side length of each square. Let's say each square has a side length of "s" units. The perimeter of one square is 4s, so the total perimeter of 10 squares in a row would be 10 * 4s = 40s units.
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Say the length of 1 side of a square is x.
If the ten squares were lined up side by side, in a line, the length of the top and bottom would both be 10x. The length of the left and right would be x. The total perimeter would be 10x + 10x + x + x which equals 22x.
The perimeter would be 40cm.
The easiest way to reason this is to consider how you could connect nine squares together while leaving the largest amount of perimeter exposed. In other words, what's the largest number of faces you can leave exposed on a set of squares that are all connected? The answer is that if you connect all of the squares in a line, then the two end squares will have three faces exposed and the other seven squares will have two faces exposed. That gives you 2 * 7 * 2cm + 3 * 2 * 2cm = 28cm + 12cm = 40cm. So the maximum perimeter you can get is 40cm. There are many other ways that you can arrange the squares to give you the same perimeter (eg. a plus sign, a zig-zag, and so on), but none that will give you more.
What is a rectangle were the area is 10 and the perimeter
Area of square = 81 cm2 so side of square = 9 cm and then perimeter = 4*side = 36 cm.
Perimeter: 6+8+10 = 24 units