5+5+3+3=16feet
108 feet is the perimeter of a rectangle with a length of 50 feet and a width of 4 feet.
The perimeter is 30 feet for this rectangle.
228 feet is the perimeter.
20 feet
Length + width = half of perimeter so width = p/2 - length ie (22-12) 10 yards.
If the perimeter is 84 feet and the length is twice the width, then the length will be 28 feet and the width will be 14 feet.
Assume it is a rectangular window (why?) Suppose the width is L feet. Then the width is L + 3 feet (Odd, because normally Length is the larger of the two) So Perimeter is 2(Length + Width) ie 38 = 2*(L + L+3) 19 = 2L + 3 16 = 2L L = 8 and then L + 3 = 11 So the window is 8 feet long and 11 feet wide.
108 feet is the perimeter of a rectangle with a length of 50 feet and a width of 4 feet.
The perimeter of a rectangle with a length of 8.5 feet and a width of 4.5 feet is 26.
If the width is 9' and the length is twice that, the length is 18'; the perimeter is twice the length plus twice the width, which is 36' + 18' = 54 feet.
Perimeter = 2*(Length + Width) = 2*(15+9) = 48 feet.
Perimeter = 2(length + width) → width = perimeter ÷ 2 - length length = 1 foot → width = 70 ft ÷ 2 - 1 ft = 34 ft; length = 2 feet → width = 70 ft ÷ 2 - 2 ft = 33 ft.
Length = 16 feetWidth = 8 feetDistance around the perimeter =Length + width + length + width = 16 + 8 + 16 + 8 = 48 feet.
The length is 3 feet
If the length to width ratio is 4 to 5 then the length to width ratio is 4 to 5no matter what the perimeter. If the perimeter is 70 feet then the sides are 15.555... and 19.444... feet respectively.
The perimeter is 30 feet for this rectangle.
If the dimensions of the rectangle are in feet, the perimeter will be in feet as well. The area will be in square feet. The area is length x width. The perimeter is 2 x (length + width) or 2 x length + 2 x width.