mn = 8 ( Product)
m + n = 6 (Sum)
Hence
m = 6 - n
Substitute
(6 -n)n = 8
Multiply out the brackets
6n - n^(2) = 8
n^(2) - 6n + 8 = 0
It is now in quadratic form and will factor
Hence
((n - 2)(n - 4) = 0
n = 2 & n = 4
So '2' & '4' are the two numbers.
Verification
2 + 4 = 6
2 x 4 = 8
2 and 6 have.
It depends on the sum of 6 and WHAT!
80 is.
8+5*3 8+15 =23
3 and 5
The sum of 8 and 6 is 14. The product is 48.
6 and 2 are a number pair with a sum of 8 and a product of 12
Numbers that have a product of 8 are 1,8 and 2,4. Their sums are 9 and 6 respectively. Numbers that have a product of 7 and a sum of 8 are 1 and 7.
6 & 8. 6 + 8 = 14 6 x 8 = 48
2 and 6 have.
The numbers that the sum of them is 8 and the product of them multiplied is 12 is 2 and 6 because 6 multiplied by 2 is 12, and 2+6 is always 8. Hope this helps!
They are: -8 and 6
-4 and -2
NO
8 and 6 8 x 6=48 8 + 6=14
The number are 2 and 4
-8