Q: What is the product of f and g in algebra?

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Linear algebra works with straight lines on a plane. Boolean algebra is a very different form of maths, being logical calculus. Let me demonstrate linear algebra: 6x=2*5 6x=10 x=5/3 Boolean logic: (There exists) x xV(not)y (implies) f(x)=f^2(g)-F(y)

d[fg(x)]/dx = df(x)/dx*g(x) + f(x)*dg(x)/dx or (fg)' = f'g + fg'

7i8

5g

Multiply the parts together.

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Assume f=f(x), g=g(x)and (f^-1)(x) is the functional inverse of f(x). (f+g)'=f'+g' (f*g)'=f'*g+f*g' product rule (f(g))'=g'*f'(g) compositional rule (f/g)'=(f'*g-f*g')/(g^2) quotient rule (d/dx)(x^r)=r*x^(r-1) power rule and applies for ALL r. where g^2 is g*g not g(g)

Linear algebra works with straight lines on a plane. Boolean algebra is a very different form of maths, being logical calculus. Let me demonstrate linear algebra: 6x=2*5 6x=10 x=5/3 Boolean logic: (There exists) x xV(not)y (implies) f(x)=f^2(g)-F(y)

In math and algebra, a product is the result of multiplication. The product of a x b is ab.

d[fg(x)]/dx = df(x)/dx*g(x) + f(x)*dg(x)/dx or (fg)' = f'g + fg'

A. G. Pinus has written: 'Boolean constructions in universal algebras' -- subject(s): Algebra, Boolean, Algebra, Universal, Boolean Algebra, Universal Algebra

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