The range of {0, 1, 2, 3, 4, 5, 6} is 6 - 0 = 6.
Chat with our AI personalities
1 (0+1) 3 (0+1+2) 6 (0+1+2+3) 10 (0+1+2+3+4) 15 (0+1+2+3+4+5) 21 (0+1+2+3+4+5+6) Notice these are the numbers you can arrange into equalateral triangles.
:−3+0+1+2 = 0 :−3*0*1*2 = 0
let f(x) = 3x^2 - 3x + 1. The roots of f is the same as asking for x where f(x) = 0. So we do it f(x) = 0, 3x^2 - 3x + 1 = 0. Using "complete the square" method 3(x^2 - x) + 1 = 0 3(x^2 + (2 . - 1/2 . x) + (-1/2)^2 -(-1/2)^2) + 1 = 0 3(x - 1/2)^2 -3/4 + 1 = 0 3(x - 1/2)^2 + 1/4 = 0 By the quadratic formula, the solution comes out to be x = [3+√(-3)]/6 and x = [3-√(-3)]/6 or x = (3+i√3)/6 and x = (3-i√3)/6 in other words, the solutions are complex numbers.
... -3, -2, -1, 0, 1, 2, 3, ...In summary, any integer that you use as an exponent is an "integral exponent".... -3, -2, -1, 0, 1, 2, 3, ...In summary, any integer that you use as an exponent is an "integral exponent".... -3, -2, -1, 0, 1, 2, 3, ...In summary, any integer that you use as an exponent is an "integral exponent".... -3, -2, -1, 0, 1, 2, 3, ...In summary, any integer that you use as an exponent is an "integral exponent".
4x2-4x-3 = 0 (2x-3)(2x+1) = 0 x = 3/2 or x = -1/2