If we denote the measure of the length side of the circumscribed square with a, then the vertexes of the inscribed square will point at the midpoint of the side, a, of the circumscribed square.
The area of the circumscribed square is a^2
The square measure of the length of the inscribed square, which is also the area of this square, will be equal to [(a/2)^2 + (a/2)^2]. Let's find it:
[(a/2)^2 + (a/2)^2]
= (a^2/4 + a^2/4)
= 2(a^2)/4
= a^2/2
Thus their ratio is:
a^2/(a^2/2)
=[(a^2)(2)]/a^2 Simplify;
= 2
The area of the square is 98 square cm. Assuming the shaded area is the remainder of the circle, its area is 55.9 square cm (approx).
The ratio is [ 4/x per unit ].
A square with an area of 2 m2 has sides of sqrt(2) m. The diameter of the inscribed circle is, therefore sqrt(2) m. The radius is sqrt(2)/2 m The area of a circle with radius sqrt(2)/2 is pi*[sqrt(2)/2]2 = pi*2/4 or pi/2 = 1.5708 m2
Square inscribed a 30 ft diameter has a diagonal equal to 30 ft. Use the Pythagorean theorem, and side^2 + side^2 = 30^2 2s^2 = 900 s^2 = 450 side length = square root of 450, simplify 15sqrt(2) = s Area = s^2 = 450 square feet Perimeter = 4s = 4*15*sqrt(2) = 60 times the square root of 2
area of triangle 1 would be 16 and the other triangle is 9 as the ratio of areas of triangles is the square of their similar sides
circumscribed means the polygon is drawn around a circle, and inscribed means the polygon is drawn inside the circle. See related links below for polygon circumscribed about a circle and polygon inscribed in a circle.
When rectangles are inscribed, they lie entirely inside the area you're calculating. They never cross over the curve that bounds the area. Circumscribed rectangles cross over the curve and lie partially outside of the area. Circumscribed rectangles always yield a larger area than inscribed rectangles.
The radius length r of the inscribed circle equals to one half of the length side of the square, 10 cm. The area A of the inscribed circle: A = pir2 = 102pi ≈ 314 cm2 The radius length r of the circumscribed circle equals to one half of the length diagonal of the square. Since the diagonals of the square are congruent and perpendicular to each other, and bisect the angles of the square, we have sin 45⁰ = length of one half of the diagonal/length of the square side sin 45⁰ = r/20 cm r = (20 cm)(sin 45⁰) The area A of the circumscribed circle: A = pir2 = [(20 cm)(sin 45⁰)]2pi ≈ 628 cm2.
If I understand your question correctly, you would need to subtract the area of the inscribed circle from the circumscribed circle. Which would approximately be 78.60cm squared.
-- 'Y' is circumscribed about 'X' -- The area of 'X' is less than the area of 'Y'.
The area of square is : 100.0
The approximate area of the circle lies between the areas of the circumscribed and the inscribed hexagons.
78.53
the area of a square is 49m^2 what is the length of one of its sides
98 cm^2
For a circle inside a square, the diameter is the same as the side length, and the area of the circle is about 78.54% of the square's area (pi/4). A(c) = 0.7854 A(s) The area of the square is L x L. (For a square, L = W). The area of the circle is PI x R^2, where R = L/2. Let's express the area of the square using A = L x L = (2R) x (2R) = 4 R^2 So, the ratio of the area of the circle to that of the square is: pi/4 or about 0.7854.
The area of the square is 98 square cm. Assuming the shaded area is the remainder of the circle, its area is 55.9 square cm (approx).