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If we denote the measure of the length side of the circumscribed square with a, then the vertexes of the inscribed square will point at the midpoint of the side, a, of the circumscribed square.

The area of the circumscribed square is a^2

The square measure of the length of the inscribed square, which is also the area of this square, will be equal to [(a/2)^2 + (a/2)^2]. Let's find it:

[(a/2)^2 + (a/2)^2]

= (a^2/4 + a^2/4)

= 2(a^2)/4

= a^2/2

Thus their ratio is:

a^2/(a^2/2)

=[(a^2)(2)]/a^2 Simplify;

= 2

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Q: What is the ratio of the area of the circumscribed square to the area of the inscribed square?
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