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I think you have not asked the question correctly.

I guess you meant that the sides of the triangle are 3, 4 and 5. Similarly you have given no indication of which angle is opposite which side.

A 3, 4, 5 triangle is a right angle triangle (5 is the hypotenuse).

Thus depending where angle B is, its sine will be:

  • If B is opposite the side of length 3, sin B = 4/5
  • If B is opposite the side of length 4, sin B = 3/5
  • If B is opposite the side of length 5, sin B = 5/5 = 1; alternatively ∠B = 90° and sin B = sin 90° = 1
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Q: What is the sin of angle B if the angles are 3 4 5?
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