Points: (3, 4) and (5, 4) Slope: (4-4)/(3-5) = 0 There is no slope and it is a straight line parallel to the x axis
Which of the following is the point-slope equation of the line with a slope equals -4 and a point of -2 3?
Points: (3, 2) and (-1, -4) Slope: (2--4)/(3--1) = 3/2 or 1.5
Points: (0, -1) and (-2, -4)Slope: 3/2
If you mean points of (5, -9) and (2, 3) then the slope is -4
The slope of a line that has the points 3, (-4), and has a slope of 2 is 2.
Points: (-4, 0) and (3, -3) Slope: -3/7
Points: (6, -4) and (3, 4) Slope: -8/3
Points: (5, 0) and (3, -4) Slope: 2
Points: (4, 5) and (-2, -4) Slope: 3/2
Slope = [(-2) - 3]/(7 - 4) = -5/3
Points: (-3, -3) and (4, -3) Slope: (-3--3)/(-3-4) = 0
Points: (3, 4) and (5, 4) Slope: (4-4)/(3-5) = 0 There is no slope and it is a straight line parallel to the x axis
3/4
Points: (3, 2) and (-1, -4) Slope: (2--4)/(3--1) = 3/2 or 1.5
Slope: (2-4)/(0--3) = -2/3 Perpendicular slope: 3/2
Points: (-6, 4) and (3, -4) Slope: -8/9