7
3y4 + 3y2 = 3y2(y2 + 1)
5y4
y times the cube root of x2y
You can divide each exponent by three; thus, you get: x4/3y4/3 This is equivalent to x (cubic root of x) y (cubic root of y).
2y3 * (-2)x-1 * 3y4 = 2*(-2)*3*(1/x)*y3*y4 = -12y7/x
3y^(4)- y^(2) = 0 Factor y^(2) [ 3y^(2) - 1] = 0 Hence y^(2) = 0 It follows that y = 0 And 3y^(2) - 1 = 0 y^(2) = 1/3 y = +/- sqrt( 1/3) = +/-0.577350269..... Hence y = 0 or y = +/-0.577350269.... to make the eq'n equal to zero.
2x - 3y = 4 x + 4y = 3 Write the augmented matrix: 2 -3 4 1 4 3 Multiply the first row by 1/2: 1 -3/2 2 1 4 3 Subtract the second row from the first row: 1 - 3/2 2 0 -11/2 -1 Multiply the second row by -2/11: 1 -3/2 2 0 1 2/11 Multiply the second row by 3/2 and add it to the first row: 1 0 25/11 0 1 2/11 Thus x = 25/11 and y = 2/11 Check: