3x + 5y = 16
5y = -3x + 16
y = -3/5 x + 16/5
By the slope-intercept form:
y = mx + b where
m = slope
b = y-intercept
Therefore, the slope is -3/5.
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3x + 5y = 16
5y = -3x + 16
y = -3/5 x + 16/5
By the slope-intercept form:
y = mx + b where
m = slope
b = y-intercept
Therefore, the slope is -3/5.
If you mean: 3x+2y = 16 then it is y = -1.5x+8
7x + 16 = 3x + 4 4x = -12 x = -3
3x + 4 = 16 3x = 16 - 4 x = 12/3 x = 4
(5, 1)
y=3x+3 -- This could be the formula for a line, where the slope is 3 and the y intercept is (0,3). In the next line the slope would be 4 and the y-intercept would be 5