Points: (6, -10) and (-15, 15)
Slope: (-10-15)/(6--15) = -25/21
-5
6x - 5y = 15 6x - 6x - 5y = 15 - 6x -5y = -6x + 15 (-5y)/-5 = (-6x)/-5 + 15/-5 y = 6/5x - 3 where 6/5 is the slope and y-intercept is -3.
Equation: y-6 = 2/5(x-10)Solution: 5y = 2x+10
If you mean points of (-10, -6) and (-1, 8) then the slope of the line is 14/9 which is in a positive direction
15y = 10x + 12 Divide both sides by '15' Hence y = (10/15)x + 12/15 Cancel down the fractions y = (2/3)x + 4/5 : This is the slope/intercept form. Hence the slope is 2/3 and the intercept is 4/5
Points: (3, 3) and (-6, -15) Slope works out as: 2
Points: (0, 5) and (10, -15) Slope: -2
EQ2
Points: (10, 8) and (15, 8) Slope: 0 It will be a straight horizontal line
slope is =( 9-15 )/ (5-3) = -6/2 = -3
6x = 10-y y = -6x+10 The slope is -6 and the y intercept is 10
15
The slope-intercept form of a line is given by the equation ( y = mx + b ), where ( m ) is the slope and ( b ) is the y-intercept. Given a slope ( m = -1 ) and a point (-10, -6), we can substitute these values into the equation to find ( b ): [ -6 = -1(-10) + b \implies -6 = 10 + b \implies b = -16. ] Thus, the slope-intercept form of the line is ( y = -x - 16 ).
10
-5
if you mean points of (-6, 2) and (4, 1) then the slope works out as -1/10
6. (10 x 15) ÷ (10 + 15) = 150 ÷ 25 = 6