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4x plus 5y 40?
If you mean: 4x+5y = 40 then y = -0.8x+8 whereas as -0.8 is the slope and 8 is the y intercept of a straight line equation
What is 5x plus 8y equals 40 in slope - intercept?
5x+8y = 40 8y = -5x+40 y = -5/8x+5 in slope intercept form
-20x 5y equals 40 changed to slope-intercept form?
Oh, dude, you just gotta rearrange that equation a bit. So, like, first divide by 5 to get -4x - y = 8. Then, if you wanna be all fancy and use slope-intercept form, just solve for y to get y = -4x + 8. And there you have it, a technically correct answer with a sprinkle of my signature humor.
What is the difference between pitch and slope?
In regards to roofs. "Pitch" is a ratio of the total rise of a roof over the total span of a building. "Slope" is a ratio of the total rise of a roof over "half" the total span of a building. A building 40 feet wide with a total roof rise of 10 feet (from the top of the supporting walls) has a pitch of 10/40 reduced to 1:4 A building of the same dimensions will have a slope of 1:2 or 6/12 on the imperial framing square.
Find the area S of the region bounded by the parabola y 5x2 the tangent line to this parabola at 2 20 and the x-axis?
First we need to find the equation of the tangent line to the parabola at (2, 20).Step 1. Take the derivative of the function of the parabola.Let f(x) = 5x^2f'(x) = 10xStep 2. Find the slope of the tangent line at x = 2. Evaluate f'(2).f'(2) = 2 x 10 = 20Step 3. Using the slope, m = 20, and the point (2, 20), find the equation of the tangent line at that point. Use the point-slope form of a line(y - y1) = m(x - x1)(y - 20) = 20(x - 2)y - 20 = 20x - 40 add 20 to both sidesy = 20x - 20Step 4. Find the points of intersections of y = 5x^2 and y = 20x - 205x^2 = 20x - 20 Divide by 5 to both sidesx^2 = 4x - 4 subtract 4x and add 4 to both sidesx^2 - 4x + 4 = 0 factor(x - 2)^2= 0x = 2Step 5. Find the intersection of the tangent line with x-axis.y = 20x - 20y = 020x - 20 = 0x = 1Since the vertex of the parabola is (0, 0) and the intersection of the tangent line with parabola is (2,20) we use the interval [0, 2] to fin the required area.Step 6. IntegrateA = ∫ [(5x^2)] dx, where the below boundary is 0, and the upper boundary is 2 minus A= ∫ (20x + 20)] dx from 1 to 2= 10/3
