If you mean: 4x+5y = 40 then y = -0.8x+8 whereas as -0.8 is the slope and 8 is the y intercept of a straight line equation
5x+8y = 40 8y = -5x+40 y = -5/8x+5 in slope intercept form
If the equation is -20x-5y=40 then the answer is -5y=20x+40 which equals y=-4x-8 If the equation is -20x+5y=40 then the answer is 5y=20x+40 which equals y=4x+8
In regards to roofs. "Pitch" is a ratio of the total rise of a roof over the total span of a building. "Slope" is a ratio of the total rise of a roof over "half" the total span of a building. A building 40 feet wide with a total roof rise of 10 feet (from the top of the supporting walls) has a pitch of 10/40 reduced to 1:4 A building of the same dimensions will have a slope of 1:2 or 6/12 on the imperial framing square.
First we need to find the equation of the tangent line to the parabola at (2, 20).Step 1. Take the derivative of the function of the parabola.Let f(x) = 5x^2f'(x) = 10xStep 2. Find the slope of the tangent line at x = 2. Evaluate f'(2).f'(2) = 2 x 10 = 20Step 3. Using the slope, m = 20, and the point (2, 20), find the equation of the tangent line at that point. Use the point-slope form of a line(y - y1) = m(x - x1)(y - 20) = 20(x - 2)y - 20 = 20x - 40 add 20 to both sidesy = 20x - 20Step 4. Find the points of intersections of y = 5x^2 and y = 20x - 205x^2 = 20x - 20 Divide by 5 to both sidesx^2 = 4x - 4 subtract 4x and add 4 to both sidesx^2 - 4x + 4 = 0 factor(x - 2)^2= 0x = 2Step 5. Find the intersection of the tangent line with x-axis.y = 20x - 20y = 020x - 20 = 0x = 1Since the vertex of the parabola is (0, 0) and the intersection of the tangent line with parabola is (2,20) we use the interval [0, 2] to fin the required area.Step 6. IntegrateA = ∫ [(5x^2)] dx, where the below boundary is 0, and the upper boundary is 2 minus A= ∫ (20x + 20)] dx from 1 to 2= 10/3
It works out as 29
Points: (40, -64) and (41, -35) Slope: 29
If you mean: 4x+5y = 40 then y = -0.8x+8 whereas as -0.8 is the slope and 8 is the y intercept of a straight line equation
The slope or gradient of a line that represented the change in savings over time would increase (in this case it would double). This is because in the example in your question, you would be saving twice as much money per unit time. As such the gradient of the line would change from 20 (20 / 1) to 40 (40 / 1).
Slope = Height/Base = 40/60 = 2/3
5x+8y = 40 8y = -5x+40 y = -5/8x+5 in slope intercept form
The graph is a straight line, with a slope of 40, passing through the point y=50 on the y-axis.
40 is larger than 06 which is the same as 6
The equation for the line can be written in slope-intercept form as y = mx + b, where m is the slope and b is the y-intercept. Since we know that the slope is -45 and the point (1, -5) lies on the line, we can write the equation as y = -45x + b. To find b, substitute the x and y values of the point into the equation and solve for b: -5 = -45(1) + b. Simplifying the equation gives b = 40. Therefore, the equation for the line is y = -45x + 40.
Its (-4, 0) and (4, 2) not (40) and (42)
A 1 in 40 slope means that for every 40 units of horizontal distance, there is a 1 unit rise. To convert this to degrees, you can use the arctangent function. The formula to convert slope to degrees is arctan(slope) = angle in degrees. Therefore, for a 1 in 40 slope, the angle in degrees would be approximately 1.43 degrees.
20